The company installs 5000 light bulbs with an average of 500 hours for each bulb. The standard deviation of 100 hours and distribution approximated by a normal curve. The percentage of bulbs that can be expected to last the period of time of less than 690 hours is 97.1%. This will make the answer to be C.
Answer:
About 12.6 years
Step-by-step explanation:
2500(1.055^x) = 5000
1.055^x = 2
x ln1.055 = ln2
x = 12.94615711
Answer:
Step-by-step explanation:
100×120=12000
101×119=12019
so 119/120 >100/101
A is correct. Cosecant is defined as the reciprocal of sine.
B is also correct...