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The surface area of the triangular prism is of 140 cm².
<h3>What is the surface area of a prism?</h3>
It is the sum of the areas of all faces of a prism. In this problem, the prism has these following faces:
- One rectangle of dimensions 8 cm and 6 + 4 + 5 = 15 cm.
- Two right triangles with sides 4 cm and 5 cm.
For a rectangle, the area is given by the multiplication of the dimensions, hence:
Ar = 8 x 15 = 120 cm²
For each right triangle, the area is given by half the multiplication of the sides, hence:
At = 2 x 0.5 x 4 x 5 = 20 cm².
Then the surface area of the prism is:
S = 120 cm² + 20 cm² = 140 cm².
More can be learned about surface area at brainly.com/question/28123954
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Answer:
u=4
v=2√3
Step-by-step explanation:
The 30-60-90 triangle theorem states that the shortest side of a triangle is half of the hypotenuse, so 2*2=4. So, the hypotenuse, <em>u</em>, is 4.
The longest leg is √3 times greater than the shortest leg, so 2*√3=2√3. So, the longest leg, <em>v</em>, is 2√3.
Answer: -2/3
3-(-1) over
-2-4
This equals 4/-6 which reduces to -2/3
