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Lynna [10]
3 years ago
10

What is the solution to the system of equations graphed below

Mathematics
2 answers:
aleksley [76]3 years ago
8 0

Answer:

Option C is correct

(1, 5)

Step-by-step explanation:

A system of equations contains two or more than two linear equations that divide two or more unknowns.

To find a solution for the system of equations,

we must find a value from the graph that is true for all equations in the given system.

We know that:

If the graphs of the equations intersect,

then there is one solution that is true for both equations.

Given the graph.

There are two lines

Equation of Blue line : y = -x+6

Equation of Red line = y = 2x+3

Since, the graph of two lines y = -x+6 and  y = 2x+3 intersects which means there is one solution that satisfies the both equation.

Therefore, the solution to the system of equations graphed is, (1, 5)

aliina [53]3 years ago
3 0
The point where the lines intersect is the point that satisfies both equations.

It is (1, 5), selection C.
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How do I solve this?
Verdich [7]

Consider the point P where the gears meet. When the smaller gear rotates clockwise, the larger one will rotate counterclockwise.

Through one rotation of the smaller gear, P will have traveled the circumference of the smaller gear, which is 8\pi in.

At the same time, a point P' on the larger gear traverses the same distance along the larger gear's circumference. This point traces out an arc that is subtended by some angle \theta. The arc is as long as the smaller gear's circumference.

The measure of a circle's interior angle subtended by an arc is proportional to a complete revolution, i.e. an angular displacement of 2\pi radians:

\dfrac{14\pi\,\mathrm{in}}{2\pi\,\mathrm{rad}}=\dfrac{8\pi\,\mathrm{in}}\theta\implies\theta=\dfrac{8\pi}7\,\mathrm{rad}\approx205.7^\circ

For part 2, we apply the same reasoning to the larger gear. In one full rotation of the larger gear, the point P' traverses the circumference 14\pi in, and so does the point P on the smaller gear.

\dfrac{8\pi\,\mathrm{in}}{2\pi\,\mathrm{rad}}=\dfrac{14\pi\,\mathrm{in}}\theta\implies\theta=\dfrac{7\pi}2\,\mathrm{rad}=630^\circ

A full rotation is 360 degrees, so the smaller gear would have rotated \dfrac{630^\circ}{360^\circ}=1.75 times.

6 0
3 years ago
Which equation could be used to find 150% of 500​
777dan777 [17]

Answer:

500x1.5

Step-by-step explanation:

8 0
4 years ago
The slope of two lines are 5/6 and 2/p. determine the value of p that will make the lines
Anni [7]
Parallel:  the lines have = slopes.  We thus need 5/6 to equal 2/p.  then 5p must equal 12, and p = 12/5.   (answer)

Check:  Is 5/6 = 2 / (12/5)?  YES

Perp.:  The lines have slopes that are negative reciprocals of one another.

Then -6/5 = 2/p,  or

 -6      2
---- = ----
  5      p             Thus, -6p = 10, and p = -5/3   (answer)
7 0
3 years ago
Read 2 more answers
Solving system of equations 2x+4=3y<br> x-2y=-7
dimaraw [331]

X = 13, Y = 10

I'm a bit tired right now, so I'm not going to explain my work, but hopefully this still helps.

Good luck with your schoolwork/homework!

---------------------------------------------------------------------

Apologies in advance for wrong answers or bad explanation.

3 0
4 years ago
Gym a charges $60 a month plus $5 dollars per visit. the monthly cost at gym b is represented by y=5x=40, where x is the number
guajiro [1.7K]
Gym B should be cheaper by $20 if you go the same number of times.
8 0
3 years ago
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