5x - 3y + 1 = 16 ⇒ 10x - 6y + 2 = 16
2x + 5y + 0 = -6 ⇒ <u>10x + 25y + 0 = -6</u>
31y + 2 = 10
<u> -2 -2</u>
<u>31y</u> = <u>8</u>
31 31
y = 8/31
5x - 3(8/31) + 1 = 16
5x - 24/31 + 1 = 16
5x + 7/31 = 16
<u> -7/31 -7/31</u>
<u>5x</u> = <u>10 24/31</u>
5 5
x = 2 24/155
(x, y) = (2 24/155, 8/31)
Equation: x + 25 = 2x - 115
Cross 115 over the 'bridge' and add it with 25: x+140 = 2x
Cross x over the 'bridge' and subtract with 2x: 140 = x
ANSWER: x
(trying to isolate/get x by itself in the equation)
5(x + 6) = 50 Distributive property [distribute 5 into (x + 6)]
5x + 30 = 50 Subtraction [subtract 30 on both sides of the equation]
5x = 20 Division [divide 5 on both sides]
x = 4
Subtraction then division, the 2nd option
Answer:
Step-by-step explanation:
The terminal arm is either in quad 1 or quad 3
Re-write with common denominator, in this case 6:
Add:
