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eimsori [14]
3 years ago
14

Help me please mathematics

Mathematics
2 answers:
Cloud [144]3 years ago
8 0
Answer: I think it’s C may be wrong though
Temka [501]3 years ago
3 0

Answer:C, 3/50

Step-by-step explanation:

Add 117, 24 and 9 to get 150. Then simplify 9/150 to get 3/50.

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Find X in this picture. ​
sweet [91]

Answer:

x is in the top left of the triangle :)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please help me with this i don’t understand much
Alexus [3.1K]

Answer:

See below

Step-by-step explanation:

Three lengths will be a triangle only if the sum of two sides is greater than the third side.

19+11 > 17

This is a triangle.

23+28> 52\\51>52\\51 \ngtr 52

This is not a triangle.

9+25> 34\\34>34\\34\ngtr 34

This is not a triangle.

13+14> 22\\27>22

This is a triangle.

8 0
3 years ago
Paaaa hellllpppp po with solution po sana​
ira [324]
<h2>Solving Equations</h2>

To solve linear equations, we must perform inverse operations on both sides of the equal sign to <em>cancel values out</em>.

  • If something is being added to x, subtract it from both sides.
  • If something is being subtracted from x, add it on both sides.
  • Same with multiplication and division. If x is being divided, multiply. If x is being multiplied, divide.

We perform inverse operations to<em> combine like terms</em>. This means to get x to one side and everything else on the other.

<h2>Solving the Questions</h2><h3>Question 1</h3>

5x+7=15

Because 7 is being added to x, subtract it from both sides:

5x+7-7=15-7\\5x=8

Because x is being multiplied by 5, divide both sides by 5:

\dfrac{5x}{5}=\dfrac{8}{5}\\\\x=\dfrac{8}{5}

Therefore. x=\dfrac{8}{5}.

<h3>Question 2</h3>

7x+4=5x-18

Here, we can group all the x values on the left side of the equation. Subtract 5x from both sides:

7x+4-5x=5x-18-5x\\2x+4=-18

To isolate x, subtract 4 from both sides:

2x+4-4=-18-4\\2x=-22

Divide both sides by 2:

\dfrac{2x}{2}=\dfrac{-22}{2}\\\\x=-11

Therefore, x=-11.

6 0
2 years ago
The cube root of 5 times the square root of 5 over the cube root of 5 to the 5th power
Fiesta28 [93]
(cube root of 5)  * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)

This becomes easier if we switch to fractional exponents:


  5^(1/3) * 5^(1/2)         5^(1/3 + 1/2)       5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3)                  5^(5/3)                 5^(5/3) 

Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.

                                                            1
Thus,  5^[5/6 - 5/3] = 5^(-5/6)  =  --------------
                                                        5^(5/6)

That's the correct answer.  But if you want to remove the fractional exponent from the denominator, do this:

    1            5^(1/6)         5^(1/6)
---------- * ------------- = --------------    (ANSWER)
5^(5/6)       5^(1/6)              5
7 0
3 years ago
Solve for x.<br><br> 6x2−2=13
makkiz [27]

Answer:

x = ±sqrt(5/2)

Step-by-step explanation:

6x^2−2=13

Add 2 to each side

6x^2−2+2=13+2

6x^2 = 15

Divide each side by 6

6/6x^2 = 15/6

x^2 = 5/2

Take the square root of each side

sqrt(x^2) = ±sqrt(5/2)

x = ±sqrt(5/2)

5 0
3 years ago
Read 2 more answers
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