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vodka [1.7K]
3 years ago
13

15÷276 i need to know for math homework its kinda hard to do​

Mathematics
1 answer:
Stells [14]3 years ago
5 0

Answer:

0.0543

(i am not fully sure)

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80 POINTS
musickatia [10]

Answer:

\large\boxed{5.95\times10^{12}}

Step-by-step explanation:

\left(1.7\times10^{-13}\right)\times\left(3.5\times10^{25}\right)\\\\=(1.7\times3.5)\times\left(10^{-13}\times10^{25}\right)\qquad\text{use}\ a^n\times a^m=a^{n+m}\\\\=5.95\times10^{-13+25}\\\\=5.95\times10^{12}

5 0
4 years ago
Factor completely:<br> 6u^2·(2u−5)^2−12u^2·(2u−5)·(u+5)
In-s [12.5K]

6u²*(2u-5)²-12u²*(2u-5)*(u+5)

-90u²*(2u-5)

8 0
3 years ago
Read 2 more answers
PLZ HELP PLZ ITS OVER DUE PLZ HELP A-S-A-P PLZ AND IF YOU DO I WILL MAKE YOURS BREANYEST PLZ HELP
zvonat [6]

Answer:

3rd one

Step-by-step explanation:

4 0
3 years ago
A movie theater charges $15 for standard viewing, $20 for 3D viewing, and $35 for Dinner and a
Ludmilka [50]

The quantity of each type of seats sold are as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.

That is, x = 4y

Also, total seats

= (x) + (y) + (z) = 3000...….............eqn(1)

Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.

  • 20x + 35y + 15z = 53000...........eqn(2)

By substituting 4y for x in equations 1 and 2; we have;

<em>5y + z = 3000</em>..…........eqn(3) and

<em>115y + 15z = 53000</em>.........eqn(4)

By solving equations 3 and 4 simultaneously; we have;

y = 200 and z = 2000

and since x = 4y

x = 800

The quantity of each type of seats sold is as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

Read more:

brainly.com/question/12413726

5 0
3 years ago
Jbk111 only PLEASE<br> 27+2,993=??
m_a_m_a [10]

3,020

fghgfdfdsdfsdfdsdfdf

7 0
3 years ago
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