3 years ago

The product of two consecutive terms of the Arithmetic sequence 5,8,11.....is 598.find the position of the term?

Mathematics

1 answer:

lbvjy [14]3 years ago

3 0

Answer:

Step-by-step explanation:

Common difference is 3.

Let x be a term in the sequence. The next term in the sequence is x+3.

x(x+3) = 598

x² + 3x - 598 = 0

x = [-3 ± √(3²-4⋅1(-598))]/[2⋅1] = [-3 ± 49]/2 = 23, -26

-26 is an extraneous solution, so x = 23.

The two terms are 23 and 26.

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