The product of two consecutive terms of the Arithmetic sequence 5,8,11.....is 598.find the position of the term?
1 answer:
Answer:
Step-by-step explanation:
Common difference is 3.
Let x be a term in the sequence. The next term in the sequence is x+3.
x(x+3) = 598
x² + 3x - 598 = 0
x = [-3 ± √(3²-4⋅1(-598))]/[2⋅1] = [-3 ± 49]/2 = 23, -26
-26 is an extraneous solution, so x = 23.
The two terms are 23 and 26.
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