Please help with these 2 questions

Finding binomial factors

serg [7]

Are there any binomial factors?

5 0

3 years ago

Find the root of 625 exponent 1/4

pashok25 [27]

Answer:

5

Step-by-step explanation:

Sqrt(625) = 25, Sqrt(25) = 5

3 0

3 years ago

Finn changes his mind and, from now on, decides to take the normal route to work everyday. On any given day, the time (in minute

Margaret [11]

Answer:

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

Step-by-step explanation:

This can be solved by the the z-score formula:

On a normaly distributed set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a value X is given by:

$Z = \frac{X - \mu}{\sigma}$

Each z-score value has an equivalent p-value, that represents the percentile that the value X is:

The problem states that:

Mean = 35, so $\mu = 35$

Variance = 81. The standard deviation is the square root of the variance, so $\sigma = \sqrt{81} = 9$ .

Find the 33rd percentile of the time it takes Finn to get to work on any given day. Do not include any units in your answer.

Looking at the z-score table, $z = -0.44$ has a pvalue of 0.333. So what is the value of X when $z = -0.44$ .

$Z = \frac{X - \mu}{\sigma}$

$-0.44 = \frac{X - 35}{9}$

$X - 35 = -3.96$

$X = 31.04$

The 33rd percentile of the time it takes Finn to get to work on any given day is 31.04 minutes.

Over the next 2 days, find the probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

$P = P_{1} + P_{2}$

$P_{1}$ is the probability that Finn took more than 40.5 minutes to get to work on the first day. The first step to solve this problem is finding the z-value of $X = 40.5$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40.5 - 35}{9}$

$Z = 0.61$

$Z = 0.61$ has a pvalue of 0.7291. This means that the probability that it took LESS than 40.5 minutes for Finn to get to work is 72.91%. The probability that it took more than 40.5 minutes if $P_{1} = 100% - 72.91% = 27.09% = 0.2709$

$P_{2}$ is the probability that Finn took more than 38.5 minutes to get to work on the second day. Sine the probabilities are independent, we can solve it the same way we did for the first day, we find the z-score of

$X = 38.5$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{38.5 - 35}{9}$

$Z = 0.39$

$Z = 0.39$ has a pvalue of 0.6517. This means that the probability that it took LESS than 38.5 minutes for Finn to get to work is 65.17%. The probability that it took more than 38 minutes if $P_{1} = 100% - 65.17% = 34.83% = 0.3483$

So:

$P = P_{1} + P_{2} = 0.2709 + 0.3483 = 0.6192$

There is a 61.92% probability that Finn took more than 40.5 minutes to get to work on the first day or more than 38.5 minutes to get to work on the second day.

7 0

4 years ago

Describe a ratio in words about the coins that compares the whole coin collection to one part of it. Then write the ratio in at

ser-zykov [4K]

Answer:

Kindly check explanation

Step-by-step explanation: A ratio which compares a whole coin collection to a part of it would be expressed in such a way that, the numerator will be the part of the coin which is being compared and the denominator being the value of the entire coin. Mathematically, It could be expressed in proportion form as ;

(Part or amount of the coin which is being compared / total value of entire coin)

A / B such that;

A = value or amount of coin which is being compared.

B = value of the entire coin.

Or in the form

A : B

part of coin being compared : blue of entire coins

3 0

3 years ago

In Ms Barclay's classroom 2/5 students play chess. 5/6 of the students play Sudoku. If there are 30 students, in her class how m

Nonamiya [84]

Answer:

12 students play chess

and 25 students play Sudoku

Step-by-step explanation:

There are 30 students in Ms Barclay's classroom.

2/5 students play chess.

i.e. $\dfrac{2}{5}\times 30$ play chess

i.e. 12 students play chess

5/6 of the students play Sudoku.

i.e. $\dfrac{5}{6}\times 30$ play Sudoku

i.e. 25 students play Sudoku

Hence, 12 students play chess

and 25 students play Sudoku

6 0

3 years ago