First, a line that is parallel, means a line that has the same slope as the original. To find the slope of the original equation, we have to solve for y.
-2x+3y=-6
3y=2x-6
y=2/3x-2
From this equation, we can see that the slope of the line is 2/3. For every 2 units you go up, you move three units over.
Now we need to use the point (-2,0) to find the equation of the parallel line.
y-y=m(x-x)
Plug in the point coordinates and the slope, and solve for the final equation of the line.
y-0=2/3(x+2)
y=2/3x+ 4/3
∠ ABD = 5(2X+1)
∠ DBC = 3X+6
∠ EBC = Y +135/2
∠ ABD and ∠ DBC are linear pairs
∴ ∠ ABD +∠ DBC = 180
∴ 5(2X+1) + 3X+6 =180
solve for x
∴ x = 13
∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135
∠ DBC = 3x+6 = 3*13+6 = 45
∠ ABD and ∠ EBC are vertical angles
∴ ∠ ABD = ∠ EBC = 135
∴ y +135/2 = 135
∴ y = 135/2
The <span>statements that are true:
--------------------------------------</span><span>
C.) x=13
E.)measure of angle EBC =135
F.) angle DBC and angle EBC are linear pairs
</span>
I think the answer would be 1/2 but i’m not sure if that’s what it’s asking
Answer:
C
Step-by-step explanation:
-5x-49>113
+49 +49
———————-
-5x>162
—- ——
-5 -5
x<32.4
