Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:84
Step-by-step explanation:
We want something that equals 19 right? Anything can work here such as
10+9=19 <---we have our outcome as 19
If you want something more complex
<span>1(10)+10-1=?
</span>When you solve that it equals 19! :)
Answer:
3.5
Step-by-step explanation:
98/8=12.25
√12.25=3.5
Answer:
12.5
Step-by-step explanation:
First, we look at the multiplication. 0.5*5 would equal 2.5. Then we would subtract that from 15. 12.5!
