In triangle ABC, BC = 29 units.
Given,
In Δ ABC, ∠A = 45°.
A perpendicular line segment traced from a triangle's vertex to its opposite side is said to be the triangle's altitude.
Let altitude meet AB on D.
So, AD = 20 units and DB = 21 units and ∠ADC = ∠BDC = 90°
In ΔADC,
tan A = DC/AD
tan 45° = DC/20
1 = DC/20
DC = 20 units
In ΔBDC,
BC² = BD² + DC² (Pythagorean Theorem)
= 21² + 20²
= 441 + 400
= 841
BC = √841
= 29
Hence, BC = 29 units.
To learn more about triangle here
brainly.com/question/2272632
#SPJ1
For this case we must represent the following expression algebraically, in addition to indicating its result:
"2 plus 9"
So, we have:

By law of the signs of the sum, we have that equal signs are added and the same sign is placed:

ANswer:
11
10 oz for 2.49. Hope I helped :)
Answer:
135°
Step-by-step explanation:
X is also 135° as is S , T U , V, W and Y
Answer:
Letter a)
Step-by-step explanation:
quizlet