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MakcuM [25]
2 years ago
11

Jasmin rakes at two different houses. it takes her 2 1/3 hours to rake leaves at the first. it takes her 1/2 of that time to rak

e at the second house. how long does it take jasmin to rake at the second house?​
Mathematics
1 answer:
Leno4ka [110]2 years ago
6 0

Answer:

Jasmin rastrilla en dos casas diferentes. le toma 2 1/3 horas rastrillar las hojas al principio. le toma 1/2 de ese tiempo rastrillar en la segunda casa. ¿Cuánto tiempo tarda el jazmín en rastrillar en la segunda casa?

Step-by-step explanation:

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Translate this phrase into an algebraic expression.
Airida [17]

Answer:

2g - 66

is the equation for given statement.

4 0
3 years ago
Can 9/43 besiplified and can 34/43 be simplified?
diamong [38]
No be because the denominator it an odd number and you can't divide an odd number hope i helped in anyway
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6 0
3 years ago
Monica has $20. She needs to buy a gallon of milk that costs $2.50. She also wants to buy yogurt, which costs $1.20 a cup. What
Kitty [74]

We are given : Cost of a gallon of milk = $2.50.

Cost of a cup of yogurt = $1.20.

Total money Monica has = $20.

Number of cups of yogurt Monica can buy = x.

And inequality made is also correct

1.20x + 2.5 ≤ 20.

Now, we need to solve it for x.

Subtracting 2.5 from both sides, we get

1.20x + 2.5 -2.5 ≤ 20 - 2.5.

1.20x ≤ 17.5

Dividing both sides by 1.20, we get

1.20x/1.20 ≤ 17.5/1.20.

x ≤ 14.5833...

Because it's less than 15, so final answer is : 14 is  greatest number of cups of yogurt Monica can buy.



3 0
3 years ago
Read 2 more answers
At homecoming, 125 tickets where sold. Tickets purchased for homecoming cost $20.5 without an activity card, and $15.75 with an
ale4655 [162]

Answer:

Nearly 83 students did not had activity card.

Nearly 42 students had an activity card.

Step-by-step explanation:

Total number of tickets sold at homecoming = 125

Cost of each  ticket without activity card = $20.5

Cost of each  ticket with activity card = $15.75

Total amount earned  = $2365

Let, the number of tickets sold without activity car d  = k

So, the number of tickets sold without card = (Total sold - k)

                                                                          = 125 - k

Now, according to the question:

$20.5(k) + $15.75(125 - k)  =  $2365

or, 20.5 k + 1968.5 - 15.75 k = 2365

⇒ 4.75 k = 2365 - 1968.5 = 396.5

⇒ k = \frac{396.5}{4.75 }  = 83.47

Hence, nearly 83 students did not had activity card.

So,the number of students that had activity card = 125 - 83.47 = 41.53 ~  42

Hence, nearly 42 students had an activity card.

4 0
3 years ago
The mass of a car tire is 17.25 kilograms. What is the mass of a car tire in grams?
nika2105 [10]

Answer:

17,250

Step-by-step explanation:

since there are 1000 grams for each kilogram

4 0
3 years ago
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