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Agata [3.3K]
3 years ago
14

Urgent please help!!

Mathematics
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

The equation is 0.5x - 5= y

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Classify each triangle by its angles and sides.<br><br>ABE<br><br>BEC<br><br>DEF<br><br>CDF​
lapo4ka [179]

Answer:

scalene right

isosceles obtuse

equilateral equilateral

scalene acute

7 0
3 years ago
Hi,so I've tried solving this problem for a while and I just don't get it,if you could give me some ideas I would appreciate it.
ziro4ka [17]

Answer:

187 cm²

Step-by-step explanation:

The bottom rectangle area is easy, it is 15*9 = 135 cm².

To find the area of the triangle, you only need the base width and its height (you don't need the hypotenuse). You can then use the formula: area triangle is base times half height.

The base width is 15-7 = 8 cm

The height is 22-9 = 13 cm

So the area of the triangle is 13*8/2 = 52 cm²

Together with the 135 of the rectangle that sums to 52+135 = 187 cm².

4 0
3 years ago
Help with physic I need ​
BARSIC [14]

Answer:

ff

Step-by-step explanation:

fff

6 0
3 years ago
Find two equivalent fractions for 2/12
Gwar [14]
1/6 (divide each by 2)
4/24 (multiply each by 2)
8 0
3 years ago
Read 2 more answers
A circle has the center of (1,-5) and a radius of 5 determine the location of the point (4,-1)
Sliva [168]

"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?

well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.

well, we can check by simply getting the distance from the center to the point (4,-1).

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}

5 0
3 years ago
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