Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
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Answer: 360 cubic cm
Step-by-step explanation: you just multiply all the numbers.
Answer:
7325.34
Step-by-step explanation:
Missing information
Take local speed ad 30 mph and express your answer in miles
Answer:
7.5 miles
Step-by-step explanation:
Time for lunch is 1 hour but once will wait for 30 minutes before served and eat.
Out of 1 hour, 30 mins is for service and eating to mean time to get from work to restaurant, to and fro is the other 30 mins
Since 30 mins is for to and fro, then one way direction takes 15 mins.
Speed, s=d/t and distance d=speed*time
Given local speed of 30 mph and time as 15 mins,
To convert minutes to hours, we divide it by 60 hence the distance is
30*15/60=7.5 miles
Therefore, the student can go to a restaurant that is 7.5 miles from the office.
