Cos
θ
=
√
5
3
or it could be cos
θ
=
√
5
−
3
Explanation:
Since sin
θ
is negative, it can be in the third or fourth quadrant
Drawing your right-angled triangle, place your
θ
in one of three corners. Your longest side will be 3 and the side opposite the
θ
will be -2. Finally, using Pythagoras theorem, your last side should be
√
5
Now, if your triangle was in the third quadrant, you would have
cos
θ
=
√
5
−
3
since cosine is negative in the third quadrant
But if your triangle was in the fourth quadrant, you would have
cos
θ
=
√
5
3
since cosine is positive in the fourth quadrant
C. 8- 6i
(3- i) to the power of 2 (expand the expression)
9- 6 i + i to the power of 2
calculate
9 - 6i - 1
calculate
8- 6i.
If you’re finding the measure of its complement, the sum of both angles will always be 90*
x+38 = 90
-38 | -38
x = 52
the measure of its complement is 52*
