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Serga [27]
4 years ago
10

210 to 35whats the percent of increase or decrease

Mathematics
1 answer:
oee [108]4 years ago
4 0

Answer:

25% of 210:

73.5

-----------------

175% of 210:

83.33333333 ~~ (on and on forever)

Step-by-step explanation:


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Im so confused pls help!
Digiron [165]

-\frac{1}{2} *(-\frac{5}{6} )+(-\frac{1}{2} )*\frac{1}{3} \\=\frac{5}{12} -\frac{1}{6} \\=\frac{5}{12} -\frac{2}{12} \\=\frac{3}{12} \\\frac{1}{4}

7 0
3 years ago
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The question is the picture thanks for helping
Vedmedyk [2.9K]

Answer:

Answer is option b)

<em>Answer is </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

a \: walking \: path \: is \: represented \: by \:  \\ y =  - 4x - 6 \\ 4x + y + 6 = 0 \\ given \: that \\ a \: new \: path \: will \: be \: built \: perpendicular  \\ \: to \:  \: the \: walking \: path \\ the \: equation \: of \: the \: line \: perpendicular \: to \\ 4x + y + 6 = 0 \: is \\ x - 4y + k = 0 \\ since \: it \: passes \: through \: ( - 4,10) \\ substitute \: x \:  =  - 4\: and \: y = 10 \: in \: required \: equation \\  - 4 - 4(10) + k = 0 \\ k = 44 \\ then \: the \: equation \: is \\ x - 4y + 44 = 0 \\ adding \: 4y \: on \: both \: sides \\ x + 44 = 4y \\ dividing \: by \: 4 \: on \: both \: sides \\ y =  \frac{x}{4}  + 11 \\ y =  \frac{1}{4} x + 11 \\ so \: the \: answer \: is \: option \: b) \:   \frac{1}{4} x + 11

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

8 0
3 years ago
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Make r the subject of the formula:<br> U=v+2t
bearhunter [10]
U=v+ 2t=
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=U/2t=r OR. r= U/2t
8 0
3 years ago
HURRY WILL MARK BRAINLIEST AND SEND VIA CASHAPP 10 BUCKS!! which point on the numberline represents -1/3?!!! HURRY ​
Pani-rosa [81]

Answer:

the answer is c because if you look at the number line it is divided into 3 equal parts and b and c is before -1 but b is -2/3 and c is -1/3 so the answer is c

4 0
3 years ago
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Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2
Verdich [7]

Answer:

(a) f'(x)=-\frac{2}{x^3}

(b) y=-0.25x+0.75

Step-by-step explanation:

The given function is

f(x)=\frac{1}{x^2}                  .... (1)

According to the first principle of the derivative,

f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}

f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}

f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}

f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}

f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}

Cancel out common factors.

f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}

By applying limit, we get

f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}

f'(x)=\frac{-2x)}{x^4}

f'(x)=\frac{-2)}{x^3}                         .... (2)

Therefore f'(x)=-\frac{2}{x^3}.

(b)

Put x=2, to find the y-coordinate of point of tangency.

f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}

Substitute x=2 in equation 2.

f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

y-y_1=m(x-x_1)

y-0.25=-0.25(x-2)

y-0.25=-0.25x+0.5

y=-0.25x+0.5+0.25

y=-0.25x+0.75

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0
4 years ago
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