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Trava [24]
3 years ago
15

What is a valence electron and how many does each element want?

Chemistry
1 answer:
dsp733 years ago
3 0
Valance electrons are the extra electrons on the outermost orbital, that hasn't been filled yet. For example, Lithium would have one valence electron, on the 2s orbital, because that is an extra electron floating around that 2s orbital, that can be shared with others, since each element's goal is to have no valence electrons. If an orbital is filled, it therefore has no valence electrons, because valence electrons are only extra electrons, if that makes any sense.

There are many groups of the periodic table. These groups categorize electrons by the amount of valence electrons they have. The group on the far left, the alkali metals, all have one valence electrons. The alkali metals include Lithium, Sodium, and other elements, so therefore give away that one electron easily, because if they give it away they won't have any valence electrons. (This is why you often see salt, sodium chloride, because sodium gives away its one valence electron to chloride, who needs one electron to have no valence electrons.) One other notable group is the noble gases, on the far right of the periodic table. These elements have no valence electrons, so therefore won't bond easily with other elements.

Hope this helped!
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A flask of fixed volume contains 1.00 mole of gaseous carbon dioxide and 88.0 g of solid carbon dioxide. the original pressure a
Lynna [10]
Are u sure this will work
5 0
4 years ago
Read 2 more answers
A solution of phosphoric acid was made by dissolving 10.8 g of H3PO4 in 133.00 mL of water. The resulting volume was 137 mL. Cal
Nesterboy [21]

Answer:

Density is: 1.05 g/ml

Mole fraction solute: 0.015

Mole fraction solvent:  0.095

Molarity: 0.80 M

Molality: 0.82 m

Explanation:

A typical excersise of solution.

It is more confortable to make a table for this.

                |   masss  |  volume  |  mol

solute       |                |                |          

solvent     |                |                |  

solution    |                |                |

Let's complete, what we have.

                 |   masss  |  volume  |  mol

solute       |  10.8g     |                |          

solvent     |                |  133 mL   |  

solution    |                |  137 mL    |

We can first, know how many moles are 10.8 g

Molar Mass H3PO4 = 97.99 g/mol

Mass / Molar mass = mol

10.8 g / 97.99 g/m = 0.110 mol

Density of water is 1 g/ml (it is a very knowly value)

From this data, we can know water mass, solvent.

Density = mass / volume

1 g/ml = mass / 133 mL

Mass = 133 g

We can also have the moles, by the molar mass of water 18 g/m

133 g / 18 g/m = 7.39 mol

                 |   masss  |  volume  |  mol

solute       |   10.8g     |                |   0.110 mol      

solvent     |   133g      |  133 mL   |  7.39 mol

solution    |   143.8g   |  137 mL   | 7.50 mol

Mass of solution will be solute mass + solvent mass

Moles of solution will be solute moles + solvent moles

Now we can calculate everything.

Molarity means mol of solute in 1 L of solution. (mol/L)

We have to convert 137 mL in L (/1000)

0.137L so → 0.110 m / 0.137L = 0.80 M

Molality means mol of solute in 1kg of solvent.

We have to convert 133g in kg (/1000)

0.133 kg so → 0.110 m/0.133 kg = 0.82 m

Density is mass / volume

Solution density will be solution mass / solution volume

143.8 g/137 mL = 1.05 g/m

Molar fraction is : solute moles / total moles  or  solvent moles/total moles.

You can also (x 100%) to have a percent of them.

Remember sum of molar fraction = 1

Molar fraction of solute = 0.110 mol / 7.50mol = 0.015

Molar fraction of solvent = 7.39 mol / 7.50 mol = 0.985

5 0
3 years ago
What is the equilibrium constant for I2+Cl2=2ICl if I2=0.50m,Cl2=o.60m and ICl=5.0
Murljashka [212]

Answer:

0.5

Explanation:

because equilibrium constant is products over reactants

substituting values will give you 0.5

8 0
3 years ago
Determine the combining capacity of iron in the compound FeCl3
Kipish [7]

Answer:

The combining capacity or power of iron in FeCl3 is +3

Explanation:

The combining capacity or power of an atom of an element is the charge which that atom possesses when it combines with other atoms to form compounds. It is also known as valency or valence.

To determine the combining capacity of iron in FeCl3, the following steps are followed:

1. Group 7 elements have a combining capacity of -1, therefore, the combining capacity of Chlorine in FeCl3 is -1

2. The sum of oxidation numbers of a neutral compound is zero, therefore, Fe + 3 × Cl = 0

Let, the combining capacity of Iron be y.

y + (-1 × 3) = 0

y - 3 = 0

y = +3

Therefore, the combining capacity of iron in FeCl3 is +3

5 0
3 years ago
For the following reaction, 2HI(g) – H (9) +1,9 the equilibrium constant k, = 2.60X10-2 at 1110 K and 2.68x10-2 at 1140 K. Calcu
iren [92.7K]

Answer:

10.63 kJ/mol is the \Delta H of the reaction.

Explanation:

To calculate \Delta H of the reaction, we use Van't Hoff's equation, which is:

\ln (\frac{K_1}{K_2})=\frac{\Delta H}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{1} = equilibrium constant at T_1

K_{2} = equilibrium constant at T_2

\Delta H = Enthalpy change of the reaction

R = Gas constant = 8.314 J/mol K

Given : K_1=2.60\times 10^{-2}

K_2=2.68\times 10^{-2}

T_1 = initial temperature = 1110 K

T_2 = final temperature = 1140 K

\Delta H = ?

Putting values in above equation, we get:

\ln(\frac{2.68\times 10^{-2}}{2.60\times 10^{-2}})=\frac{\Delta H}{8.314J/mol.K}[\frac{1}{1110 K}-\frac{1}{1140 K}]

\Delta H=10,627.617 J/mol=10.63 kJ/mol

10.63 kJ/mol is the \Delta H of the reaction.

8 0
3 years ago
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