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kirill115 [55]
2 years ago
15

Sea Anemones, algae and seaweed can be found at what part of intertidal zone?

Biology
1 answer:
Basile [38]2 years ago
6 0

Answer:

Middle Intertidal

Explanation:

Middle Tide Zone: Also called the Lower Mid-littoral Zone. This turbulent area is covered and uncovered twice a day with salt water from the tides. Organisms in this area include anemones, barnacles, chitons, crabs, green algae, isopods, limpets, mussels, sea lettuce, sea palms, sea stars, snails, sponges, and whelks.

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When DNA replication occurs before meiosis, the original DNA strand CAG CCG TAG is copied into complementary strand GTC ACA GGC
dedylja [7]
<span>The correct answer is B. Insertion. In this particular insertion there is an insert of three bases. Complementary strands in DNA are the opposite strand, so Adenine is coupled to Thymine and Guanine is coupled to Cytosine. So the complementary sequence (also called the antisense strand) of the original would be GTC GGC ATC, there's an extra 3 bases in there: ACA.</span>
5 0
3 years ago
Read 2 more answers
En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
Ilya [14]

Answer:

Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

3 0
2 years ago
Which one of the following is NOT a function of sertoli cells?
zimovet [89]

Answer:

The correct answer will be option-B.

Explanation:

Sertoli cells are the large somatic cells present in the testis which helps in the formation of spermatozoa. The Sertoli cells create a suitable environment for the production and maturation of the sperms as they produce certain molecules which nourishes the sperms.

The Sertoli cells act as a barrier between the testis and blood and secrete enzymes like inhibin. They eliminate the apoptotic germ cells and also produce seminiferous fluid to nourish the sperm. They do not play any role in primary spermatocytes.

Thus, Option-B is the correct answer.

4 0
3 years ago
What molecule is most favored by mitochondria and used by the body as quick energy?
Maru [420]

Cycle of urea or Ornithine Cycle

8 0
2 years ago
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Which process in the light-dependent reactions results in the release of hydrogen ions, electrons, and oxygen?
vivado [14]
The answer will be It's Chemiosmosis.
4 0
2 years ago
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