No. Because 33 $ is the money deducted from the 60 $. Dawn bought everything for less than 60 $.
So, if Dawn purchases everything on the rack with a 30% discount and 15% coupon the total will indeed make 45%.
We have to take 100% - 45%= 55% to know the reduction number. Let's proceed to the calculations now.
100%= 60 $
1%=60/100
55%= 60/100 × 55 = 33 $
Now <u>NOTE</u><u>;</u><u> </u><u>33</u><u> </u><u>$</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>money</u><u> </u><u>reduced</u><u> </u><u>from</u><u> </u><u>the</u><u> </u><u>60</u><u> </u><u>$</u><u>.</u><u> </u><u>So</u><u>,</u><u> </u><u>logically</u><u>,</u><u> </u><u>33</u><u> </u><u>$</u><u> </u><u>isn't</u><u> </u><u>the</u><u> </u><u>amount</u><u> </u><u>which</u><u> </u><u>Dawn</u><u> </u><u>purchased</u><u> </u><u>the</u><u> </u><u>whole</u><u> </u><u>rack</u><u>. </u>
To find the amount at which she purchased everything, we need to do,
60 $ - 33 $ = 27 $
Answer:
it's the 2nd one because
Step-by-step explanation:
have a nice day
<h3>
Answer: Choice A) 212 square meters</h3>
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Explanation:
14.10 has four sig figs. The 0 at the end is significant. This measurement is accurate to the hundredths place. If the author wrote 14.1, then it would be accurate to the tenths place with three sig figs.
15.0 has three sig figs. The 0 is significant. If they wrote 15 or 15. then we'd be dealing with 2 sig figs instead; however they placed the 0 there to tell the reader "this measurement is accurate to the tenths place"
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Multiply the values given
14.10*15.0 = 211.5
Round that to three sig figs. We pick the smaller sig fig count to round to since we cannot be certain it is accurate to four sig figs. In a sense, we pick the weakest link and use that to determine rounding when it comes to multiplication and division.
This means 211.5 rounds to 212
Given:
Quadrilateral QRST has diagonals that do NOT bisect each other, are congruent and are not perpendicular.
By checking the options:
Rhombus, rectangle and the square each of them the diagonals bisect each other
So, the answer will be option 4) Isosceles Tra
all of those r correct :)