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VARVARA [1.3K]
2 years ago
13

Put the number in the boxes m

Mathematics
1 answer:
ella [17]2 years ago
7 0

Answer:

Step-by-step explanation:

25 in m<MNT 6 in <mNTQ

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Find the center and radius of the circle whose diameter has an endpoint at (-3, -4) and the origin.
Zina [86]

Given end points of diameter,

(x1,y1)=(-3,-4)

(x2,y2)=(0,0)

Now,

the equation of circle is,

(x-x1)(x-x2)+(y-y1)(y-y2)=0

or, (x+3)(x-0)+(y+4)(y-0)=0

or, x^2 +3x +y^2 +4y =0

or, x^2 +y^2 +3x + 4y=0

which is in the form of x^2 +y^2 +2gx +2fy + c=0

where,

g=3/2

h=2

c=0

Now,

radius(r) =  \sqrt{ {g}^{2}  +  {f}^{2} - c  } \\  =  \sqrt{ \frac{ {3}^{2} }{ {2}^{2} } +  {2}^{2}  - 0 }  \\  =  \sqrt{ \frac{9}{4}  + 4}  \\  =   \sqrt{ \frac{25}{4} }  \\  =  \frac{5}{2}

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3 years ago
If a system of linear equations has an infinite number of solutions, what do you know about the graph of the system?
exis [7]
The answer is B because they never pass through each other therefore it has infinite possibilities
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2 years ago
Find the missing exponent
Hunter-Best [27]

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Because 2×(-6) is - 12

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What is Pi dumbed down?
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Answer:

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A few ways. you can enter it into a calculator for one, but the easiest way would be to reference a unit circle and look for an ordered pair where sin (the y value), is equal to -1/2

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because sin is the y value, it will additionally be in the quadrants III or IV based on the fact that (-1/2) as a sin value IS a negative and would have to be found in a quadrant in which sin is negative (the lower half of a coordinate plane, in this case)
8 0
3 years ago
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