I’m guessing that this is for systems of equations?
n - nickels
d - dimes
These are the equations you start off with.
n = 5d-2
0.95 = 0.10d+0.05n
Substitute the top equation for n into the variable n in the bottom equation.
0.95 = 0.10d+0.05(5d-2)
Solve for d.
0.95 = 0.10d+0.25d-0.10
1.05 = 0.35d
3 = d
Substitute d into the top equation and solve for n.
n = 5(3)-2
n = 15-3
n = 12
There are 3 dimes and 12 nickels in the coin purse! Hope this helped <3
-x^2+2x+3=x^2-2x+3 add x^2 to both sides
2x+3=2x^2-2x+3 subtract 2x from both sides
3=2x^2-4x+3 subtract 3 from both sides
2x^2-4x=0 factor
2x(x-2)=0
So x=0 and 2
Answer:
A
Step-by-step explanation:
A good trick for trigonometric functions is to remember SOHCAHTOA:
Sin=<u>O</u>pposite over <u>H</u>ypotenuse
Cos=<u>A</u>djacent over <u>H</u>ypotenuse
Tan=<u>O</u>pposite over <u>A</u>djacent
The red arrows on the attachment indicate where opposite, hypotenuse, and adjacent are for angle A.
So in this case, the sin of angle A (opposite over hypotenuse) would be
and cos A (adjacent over hypotenuse) would be
.
I hope this helps!