What is the domain of the function y=x-1
1 answer:
Answer:
All rational numbers or all numbers
Step-by-step explanation:
The function is a linear positive slope equation, which looks like the screenie below. Lines always travel forever, and since it is a linear line with a slope, it will be forever going in both directions.
Domain is the x-values that a function has, while range is the y-values.
Since the domain and range are infinite, it is all real numbers.
Hope this helps!
Edit: forgot the image
I zoomed out 2 million units out so you get what im saying kinda
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Answer:
Step-by-step explanation:
The equation of the line through the point &
can be represented by:
Making m the subject;
∴
we need to carry out the equation of the line through (0,1) and (1,2)
i.e
y - 1 = m(x - 0)
y - 1 = mx
where;
m = 1
Thus;
y - 1 = (1)x
y - 1 = x ---- (1)
The equation of the line through (1,2) & (4,1) is:
y -2 = m (x - 1)
where;
∴
-3(y-2) = x - 1
-3y + 6 = x - 1
x = -3y + 7
Thus: for equation of two lines
x = y - 1
x = -3y + 7
i.e.
y - 1 = -3y + 7
y + 3y = 1 + 7
4y = 8
y = 2
Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7
∴
Yuck, trig. I'm doing college trig at this very moment.
the top half (1+(2sinθ)cosθ)=1+sin(2θ)
because 2sinθcosθ=sin(2θ) is an identity
Using polynomial division your answer becomes:
(csc θ)(sec θ)+2
the top half (1+(2sinθ)cosθ)=1+sin(2θ)
because 2sinθcosθ=sin(2θ) is an identity
Using polynomial division your answer becomes:
(csc θ)(sec θ)+2