Answer:
what are the given values for x?
Step-by-step explanation:
i don't know what the given values for x are
but if you know them, here's an example
let's say x=4
y=(4)+2
y=6
Answer:
<u><em>Hi there the correct answer will be is B) (-1,5), (1, 3), (3, 1), (5,0)</em></u>
hope it helps to your question!
Y - y1 = m(x - x1)
slope(m) = 6/7
(-9,6)....x1 = -9 and y1 = 6
now we sub...pay close attention to ur signs
y - 6 = 6/7(x - (-9)....not done yet
y - 6 = 6/7(x + 9) <===
18/20=K/110
20K= 110*18
20K= 1980
K= 99
Answer:
x^2 + y^2 + 16x + 6y + 9 = 0
Step-by-step explanation:
Using the formula for equation of a circle
(x - a)^2 + (y + b)^2 = r^2
(a, b) - the center
r - radius of the circle
Inserting the values given in the question
(-8,3) and r = 8
a - -8
b - 3
r - 8
[ x -(-8)]^2 + (y+3)^2 = 8^2
(x + 8)^2 + (y + 3)^2 = 8^2
Solving the brackets
( x + 8)(x + 8) + (y +3)(y+3) = 64
x^2 + 16x + 64 + y^2 + 6y + 9 = 64
Rearranging algebrally,.
x^2 + y^2 + 16x + 6y + 9+64 - 64 = 0
Bringing in 64, thereby changing the + sign to -
Therefore, the equation of the circle =
x^2 + y^2 + 16x + 6y + 9 = 0
