Honestly I tried looking it up to get atleast something, but my best answer would have to be B.
Take this answer with a grain of salt, a lot of it
Answer:
Step-by-step explanation:
Hello!
The variable of interest is
X: speed of a vehicle along a stretch of I-10 (mph)
This variable has a normal distribution with mean μ= 81 mph and a standard deviation σ= 8 mph.
The speed limit in the said stretch is 65 mph.
You need to calculate the probability of picking a car at random and its speed be at most 65 mph, symbolically:
P(X≤65)
To reach the probability, you need to use the standard normal distribution. To standardize the value fo X you have to subtract the value of μ and then divide it by σ:
P(Z≤(65-81)/8)= P(Z≤-2.00)
Now you look for the corresponding probability in the table of the standard normal distribution, since the value is negative you have to use the left entry. The integer and first decimal numbers are in the first column and the second decimal number is in the first row.
P(Z≤-2.00)= 0.0228
I hope it helps!
Answer:
A. -2x+29=14
step-by-step explanation:
3(x+9)-(5x-2)=14
multiply
3x+27-5x+2=14
add like terms
-2x+29=14
Answer:
sin = opposite/hypotenuse
Step-by-step explanation:
16/20
Answer:
x ≈ 15.9
Step-by-step explanation:
a straight line is equal to 180 degrees
so we now know that 9x + 8 + 29 = 180
combine like terms 9x + 37 = 180
now subtract 37 from both sides 9x = 143
now divide both sides by the value of 9 x ≈ 15.9