Answer:
In the explanation
Step-by-step explanation:
a) Multiply the second equation by 2, subtract both lines. You get x = -3. Plug this in to get y, y = -2
b) Multiply the first equation by 2, add both lines. You get x = 8. Plug this in to get y, y = -3
c) Multiply the first equation by 5, subtract both lines. You get y = 1. Plug this in to get x, x = -3
d) Multiply the first equation by 2 and the second one by 3, add both lines. You get x = 1. Plug this in to get y, y = 4
Hope this helps!
Answer: a) AB = ![\left[\begin{array}{ccc}-14&26\\-11&22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-14%2626%5C%5C-11%2622%5Cend%7Barray%7D%5Cright%5D)
; b) ![\left[\begin{array}{ccc}5&-5\\13&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-5%5C%5C13%269%5Cend%7Barray%7D%5Cright%5D)
; c) No, they are different; d) No, they are never the same;
Step-by-step explanation:
a) A = ![\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D)
, B = ![\left[\begin{array}{ccc}-2&1\\-3&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C-3%267%5Cend%7Barray%7D%5Cright%5D)
. This multiplication is possible, because matrix A has 2 columns and matrix B has 2 rows. When those value are equal, the multiplication is possible.
AB = . =
b) BA = . =
c) As, we can see, parts a and b are differents.
d) With matrices, multiplication is not commutative, which means AB≠BA
Answer:The answer is CCCCCCCCTheCCCC
Step-by-step explanation:
Answer:
I think it's 5 triangle are needed to make star
