Which expression correctly represents three less than the product of a number and two increased by five?

Write a linear equation in slope intercept form to model situation: A telephone company charges $28.75 per month plus $0.10 a mi

Art [367]

y=10x+28.75 This is the answer, use slope

5 0

2 years ago

A part time seamstress made $8881.93 last year. If she claimed herself as an exemption for $3650 and had a $5700 standard deduct

Rainbow [258]

Answer:

c

Step-by-step explanation:

3 0

2 years ago

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct. Suppose that one of the st

Alex

Answer:

0.0111% probability that he answers at least 10 questions correctly

Step-by-step explanation:

For each question, there are only two outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent from other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct.

This means that $n = 15, p = \frac{1}{5} = 0.2$

What is the probability that he answers at least 10 questions correctly?

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.2)^{10}.(0.8)^{5} = 0.0001$

$P(X = 11) = C_{15,11}.(0.2)^{11}.(0.8)^{4} = 0.000011$

$P(X = 12) = C_{15,12}.(0.2)^{12}.(0.8)^{3} \cong 0$

$P(X = 13) = C_{15,13}.(0.2)^{13}.(0.8)^{2} \cong 0$

$P(X = 14) = C_{15,14}.(0.2)^{14}.(0.8)^{1} \cong 0$

$P(X = 15) = C_{15,15}.(0.2)^{15}.(0.8)^{0} \cong 0$

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.0001 + 0.000011 = 0.000111$

0.0111% probability that he answers at least 10 questions correctly

3 0

2 years ago

(23.01) In a randomized comparative experiment on the effect of dietary calcium on blood pressure, researchers divided 58 health

Paul [167]

Answer:

$113.7-2.154\frac{9.1}{\sqrt{29}}=110.06$

$113.7+2.154\frac{9.1}{\sqrt{29}}=117.34$

And the 96% confidence is given by (110.06; 117.34)

Step-by-step explanation:

Information given

$\bar X=113.7$ represent the sample mean

$\mu$ population mean (variable of interest)

s=9.1 represent the sample standard deviation

n=29 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=29-1=28$

The Confidence is 0.96 or 96%, the significance is $\alpha=0.04$ and $\alpha/2 =0.02$ , and the critical value would be $t_{\alpha/2}=2.154$

Replacing the info we got:

$113.7-2.154\frac{9.1}{\sqrt{29}}=110.06$

$113.7+2.154\frac{9.1}{\sqrt{29}}=117.34$

And the 96% confidence is given by (110.06; 117.34)

5 0

3 years ago

Can someone help me please

Lisa [10]

Answer:

perimeter is 12x-6

Step-by-step explanation:

perimeter is the sum of all sides

3(x+2) + 2x+11 + 7x-23

distribute the 3 in the first term, then combine 'like terms'

3x+6 + 2x+11 + 7x-23

3x+2x+7x + 6+11+(-23)

12x-6

4 0

1 year ago

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Which expression correctly represents three less than the product of a number and two increased by five? ​

Which expression correctly represents three less than the product of a number and two increased by five?