Answer:
1.19
Step-by-step explanation:
Hope this helps :) I try to just get straight to the point so sorry for no work
<span>Let x=time required to mow the lawn if both work together
Then both work at the rate of 1/x lawn per min
fred works at the rate of 1/60 x
</span>Bullwinkle <span>at the rate of 1/90 x
</span>1/60 + <span>1/90 = 3/180 + 2/180 = 5/180 = 1/36
</span>
<span>rate of 1/x lawn per min so 1/36 =1/x
</span>
x= 36 min
fred mow <span>1/60 x = 1/60x36 =36/60= 9/15 of the lawn
</span><span>Bullwinkle mow 1/90 x 36 = 36/90 = 6/15 of the lawn </span>
10 / 4 = 2.5
2.5 x 9 = 22.5
x = 22.5
Answer:
area = 1/2× base×height
<u>1</u>×5.8×2.4
2
<u>1</u><u>3</u><u>.</u><u>9</u><u>2</u>
2
=6.96cm²