Answer:
2.5cm
Step-by-step explanation:
area of trapezium = 4 * area of parallelogram
1/2(a+b)*h=4* bh
1/2(5+11)*4= 4* 3.2x
8*4=4*3.2x
8/3.2=x
2.5cm=x
<u>Given</u>:
Given that the data are represented by the box plot.
We need to determine the range and interquartile range.
<u>Range:</u>
The range of the data is the difference between the highest and the lowest value in the given set of data.
From the box plot, the highest value is 30 and the lowest value is 15.
Thus, the range of the data is given by
Range = Highest value - Lowest value
Range = 30 - 15 = 15
Thus, the range of the data is 15.
<u>Interquartile range:</u>
The interquartile range is the difference between the ends of the box in the box plot.
Thus, the interquartile range is given by
Interquartile range = 27 - 18 = 9
Thus, the interquartile range is 9.
1 cubic meter = 100 cm * 100 cm * 100 cm = 1 x 10^6 cc
1 kilogram = 1,000 grams
13.6 g / cc
If we had a cubic meter of mercury, its mass would be (or it would "weigh") 13.6 * 1,000,000 = 13,600,000 grams or 13,600 kilograms.
And so its density would be 13,600 kg / cubic meter.
Answer:
Option B. 
Step-by-step explanation:
we know that
The area of a circle is equal to
we have
substitute
Remember that
radians subtends the complete circle of area 
so
by proportion
Find the area of the related sector for a central angle of 
radians
Let
x------> the area of the related sector
