D. The "a" value stretches the function vertically by a factor of absolute value of a.
Answer:
a. 144 ft
b. 5 s
Step-by-step explanation:
h = -16t² + 64t + 80
a. This is a parabola, so the maximum height is at the vertex.
t = -64 / (2 × -16)
t = 2
h = -16(2)² + 64(2) + 80
h = 144
The apple reaches a maximum height of 144 ft.
b. 0 = -16t² + 64t + 80
0 = t² − 4t − 5
0 = (t + 1) (t − 5)
t = -1 or 5
t must be positive, so it takes 5 seconds to reach the ground.
Answer:
636
Step-by-step explanation:
5xyz+3y
5(2.5)(12)(4)+3(12)
(12.5)(48)+36
600+36
636
Answer: The flagpole is about 22.3 feet tall.
This is roughly the size of a two story building, assuming each floor is 10 feet or so.
Since this height is under 25 ft, this flagpole is in compliance with the regulation.
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Work Shown:
The horizontal leg of the triangle is 36 ft. This is the adjacent leg to the reference angle 25 degrees.
The vertical leg of the triangle is x-5.5, and this leg is the opposite side to the reference angle 25 degrees.
Use the tangent rule to connect the opposite and adjacent sides.
Solve for x.
tan(angle) = opposite/adjacent
tan(25) = (x-5.5)/36
36*tan(25) = x-5.5
x-5.5 = 36*tan(25)
x = 36*tan(25)+5.5
x = 22.28707569358
x = 22.3 ft is the approximate height of the flagpole
Make sure your calculator is in degree mode.
The height is not over 25 ft, so this flagpole meets the requirements.
38/14= 2 10/14= 2 5/7
The answer is 2 5/7