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Aleks [24]
3 years ago
10

Find the exact values of sin(u/2) cos(u/2) and tan(u/2) given sin u=24/25 and pie/2 < u < pie

Mathematics
1 answer:
vlada-n [284]3 years ago
8 0

Recall the double/half angle formulas:

\cos^2\dfrac x2=\dfrac{1+\cos x}2

\sin^2\dfrac x2=\dfrac{1-\cos x}2

We're given \sin u=\frac{24}{25}, and since u is between π/2 and π, we expect \cos u to be negative. So from the Pythagorean identity, we find

\sin^2u+\cos^2u=1\implies\cos u=-\sqrt{1-\sin^2u}=-\dfrac7{25}

Also, we know \frac u2 will fall between π/4 and π/2, so both \sin\frac u2 and \cos\frac u2 will be positive. Then we find

\cos\dfrac u2=\sqrt{\dfrac{1+\cos u}2}=\dfrac35

\sin\dfrac u2=\sqrt{\dfrac{1-\cos u}2}=\dfrac45

and it follows that

\tan\dfrac u2=\dfrac{\sin\frac u2}{\cos\frac u2}=\dfrac43

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