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Aleks [24]
3 years ago
10

Find the exact values of sin(u/2) cos(u/2) and tan(u/2) given sin u=24/25 and pie/2 < u < pie

Mathematics
1 answer:
vlada-n [284]3 years ago
8 0

Recall the double/half angle formulas:

\cos^2\dfrac x2=\dfrac{1+\cos x}2

\sin^2\dfrac x2=\dfrac{1-\cos x}2

We're given \sin u=\frac{24}{25}, and since u is between π/2 and π, we expect \cos u to be negative. So from the Pythagorean identity, we find

\sin^2u+\cos^2u=1\implies\cos u=-\sqrt{1-\sin^2u}=-\dfrac7{25}

Also, we know \frac u2 will fall between π/4 and π/2, so both \sin\frac u2 and \cos\frac u2 will be positive. Then we find

\cos\dfrac u2=\sqrt{\dfrac{1+\cos u}2}=\dfrac35

\sin\dfrac u2=\sqrt{\dfrac{1-\cos u}2}=\dfrac45

and it follows that

\tan\dfrac u2=\dfrac{\sin\frac u2}{\cos\frac u2}=\dfrac43

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A "line of best fit" is one that minimizes some measure of deviation from the line. Usually, what is minimized is the square of the deviations. Choosing two points to draw the line through may be convenient, but does not necessarily result in a line of best fit.

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