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Aleks [24]
3 years ago
10

Find the exact values of sin(u/2) cos(u/2) and tan(u/2) given sin u=24/25 and pie/2 < u < pie

Mathematics
1 answer:
vlada-n [284]3 years ago
8 0

Recall the double/half angle formulas:

\cos^2\dfrac x2=\dfrac{1+\cos x}2

\sin^2\dfrac x2=\dfrac{1-\cos x}2

We're given \sin u=\frac{24}{25}, and since u is between π/2 and π, we expect \cos u to be negative. So from the Pythagorean identity, we find

\sin^2u+\cos^2u=1\implies\cos u=-\sqrt{1-\sin^2u}=-\dfrac7{25}

Also, we know \frac u2 will fall between π/4 and π/2, so both \sin\frac u2 and \cos\frac u2 will be positive. Then we find

\cos\dfrac u2=\sqrt{\dfrac{1+\cos u}2}=\dfrac35

\sin\dfrac u2=\sqrt{\dfrac{1-\cos u}2}=\dfrac45

and it follows that

\tan\dfrac u2=\dfrac{\sin\frac u2}{\cos\frac u2}=\dfrac43

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31 miles

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I can’t fail please help
scoray [572]

Hey there!

The answer is 6:54

The time on the clock shows 6:20, because the hour hand is after the 6, and the minute hand is on the 4 (which we multiply by 5 to get the minutes).

If it takes her 8 minutes to walk to the bus, 10 to pack lunch, and 16 to get dressed, that's a total of 8 + 10 + 16 minutes, or 34 minutes.

So, we add that to the minutes, so 20 + 34 = 54, therefore the time is 6:54 when she arrives.

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Give the value of x .<br><br> A. 60 degrees<br> B. 180 degrees<br> C. 120 degrees<br> D. 45 degrees
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x=120°

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sum of all angles in a triangle is equal to 180

let the unknown angle be

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60 + 60 +  \alpha  = 180 \\  \alpha  = 180 - 60 - 60 \\  \alpha  = 60 \\

\alpha  + x = 180 \\ x = 180 -  \alpha  \\ x = 180 - 60 \\ x = 120

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Trevon is helping his sister study for her geometry test while staying at a hotel.
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Option (C) -: The hotel floors are parallel to each other, and the elevator moves in a path that is perpendicular to them both.

<h3>What is parallel and perpendicular ?</h3>

In geometry two lines are parallel to each other when they have no intersecting point and the distance between them is constant.

Two lines are perpendicular if they have an intersecting point and they intersect each other at at 90°.

From the given figure we can observe the distance between the floor ceiling of 3rd and 6th floor is constant therefore they are parallel to each other.Now if we imagine the elevator going up and down an imaginary line (meeting line of two elevator doors) would intersect them at an angle of 90°.

∴The hotel floors are parallel to each other, and the elevator moves in a path that is perpendicular to them both.

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