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victus00 [196]
3 years ago
14

Sheila, janice, and katen, working together at the same rate, can complete a job in 3 1/3 days. Working at the same rate, how mu

ch of the job could janice and caren do in 1 day
Mathematics
1 answer:
pychu [463]3 years ago
3 0

Answer:

Janice and Karen could do in 1 day:

  • <u>20% of the job</u>.

Step-by-step explanation:

To identify how much of the job could janice and caren do in 1 day, first, we must find how much of the job make just 1 person at the same rate:

If three persons make a job in 3 1/3 days, 1 person make the job in x:

  • 3 persons ⇒ 3 1/3 days or 10/3 days
  • 1 person ⇒ x

Then:

  • x=\frac{1 person*\frac{10}{3}days }{3 persons} (we cancel the unit "persons")
  • x=\frac{\frac{10}{3}days }{3}
  • x = 10 days

Just a person would need 10 days to complete a job, now, we're gonna divide this value in 2 to obtain the time that need two persons to complete a job:

  • Time to complete a job between 2 persons = \frac{10}{2}days
  • Time to complete a job between 2 persons = 5 days

How two persons need 5 days to complete a job (in this case, the two persons are Janice and Karen), we can make a simple rule of three to obtain the percentage made in 1 day:

  • 5 days ⇒ 100% of a job
  • 1 day ⇒ x

Then:

  • x=\frac{1*100}{5} (you can use the % if you want, the result is the same)
  • x=\frac{100}{5}
  • x=20

As you can see, <u><em>Janice and Karen just in a day could do 20% of the job</em></u>.

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Since C = pi*d, solving for d would give 1

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In any given season, a soccer team plays 65% of their games at home. When the team plays at home, they win 83% of their games. W
kodGreya [7K]

Answer:

29.9%

Step-by-step explanation:

We have that 65% of the games are at home, therefore 35% (100 - 65) are away from home.

We have that at home, they win 83% of the matches, therefore 17% (100 -83) lose them.

Also away from home they win 26% of the games, which means that 74% (100 -26) lose them.

We are asked that if the team does not win the game, find the probability that the game was played at home.

Then the favorable cases would be that he has played at home and that he has lost, that is, 65% (home games) and 17% (lost at home), the probability would be:

65% * 17% = 0.1105

Now, the probability that he loses, either at home or away from home, would be the sum of the previous probability plus when he loses away, which would be 35% of the away games, the 74% who are the losers, is say:

74% * 35% = 0.259

Therefore the probability would be:

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8 0
3 years ago
The two cross sections shown are taken parallel to their respective bases. The cross sections have the same area. If the heights
marishachu [46]

Answer:

489.40\,\,cm^3

Step-by-step explanation:

Given:

The given two cross-sections have the same area such that the heights of the two solids are equal.

To find: volume of the cylinder

Solution:

Let r represents the radius of the cylinder.

Area of the cross-section of the cylinder ( i.e., area of a circle) = area of the cross-section of the other solid (are of the rectangle)

\pi r^2 =3.8\times 8.1\\r^2=\frac{3.8\times 8.1}{\pi}

Height of the cylinder (h) = 15.9 cm

Volume of the cylinder =\pi r^2 h

=(\pi)\frac{3.8\times 8.1}{\pi}(15.9)

3.8\times 8.1\times 15.9=489.40\,\,cm^3

8 0
3 years ago
Given f(x)= -x - 2, find f(3)
kogti [31]

Answer:

- 5

Step-by-step explanation:

Step 1:

f ( x ) = - x - 2

Step 2:

f ( 3 ) = - 3 - 2

Answer:

- 5

Hope This Helps :)

6 0
3 years ago
Read 2 more answers
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