Solving for <em>Angles</em>

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
Solving for <em>Edges</em>

You would use this law under <em>two</em> conditions:
- One angle and two edges defined, while trying to solve for the <em>third edge</em>
- ALL three edges defined
* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
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Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:
- Two angles and one edge defined, while trying to solve for the <em>second edge</em>
- One angle and two edges defined, while trying to solve for the <em>second angle</em>
- ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]
* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.
I am delighted to assist you at any time.
Answer:
1
Step-by-step explanation:
6x - 3 =3
6x =3 +3
6x =6
x=6 :6
x=1
Answer:
3/10
Step-by-step explanation:
Brandon's jokes does the audience think are funny = 30%
What fraction of Brandon's jokes does the audience think are funny?
Express the percentage as a fraction
= 30%
= 30 / 100
= 3/10
The fraction of Brandon's jokes that the audience think are funny is 3/10
The result follows directly from properties of modular arithmetic:

That is,

means we can write
for some integer
. Then

and taken mod 12, the first term goes away, so

etc
If I should solve i need the table given to you