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Artyom0805 [142]
3 years ago
7

Can you help me with this problem: Elena and Jada both read at a constant rate, but Elena reads more slowly. For every 4 pages t

hat Elena read, Jada can read 5. Complete the table. (Look at photo for the table.)

Mathematics
1 answer:
Paraphin [41]3 years ago
7 0

4 pages Elena = 5 pages Jada

To figure out how many pages Jada reads if Elena reads 1, divide 5 by 4: 1.25. This means that for every 1 page Elena reads, Jada reads 1.25 pages.

So if Elena reads 9 pages, multiply 1.25 by 9: 11.25 pages that Jada reads.

For S pages read by Elena, this is a variable, so I’m assuming it means for every S pages, Jada reads 1.25S

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Yal my someone please help me with this, its teh last thing
USPshnik [31]

1) 2 1/3 is also equal to 7/3

4 1/5 is also equal to 21/5

you need to make the denominators the same so you have to find the lowest common multiple, which is 15 since both 5 and 3 can be times by to make 15

you need to also times the numerators by the number you're timesing the denominator by

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21/5 x 3 = 63/15

now add those together

35/15 + 63/15 = 98/15

now just convert 98/15 back to a mixed fraction

98/15 = 6 8/15

the answer is..

6  \frac{8}{15}

I'll do the others in a different answer!!

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