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Artyom0805 [142]

2 years ago

7

Can you help me with this problem: Elena and Jada both read at a constant rate, but Elena reads more slowly. For every 4 pages t

hat Elena read, Jada can read 5. Complete the table. (Look at photo for the table.)

1 answer:

Paraphin [41]2 years ago

7 0

4 pages Elena = 5 pages Jada

To figure out how many pages Jada reads if Elena reads 1, divide 5 by 4: 1.25. This means that for every 1 page Elena reads, Jada reads 1.25 pages.

So if Elena reads 9 pages, multiply 1.25 by 9: 11.25 pages that Jada reads.

For S pages read by Elena, this is a variable, so I’m assuming it means for every S pages, Jada reads 1.25S

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A local hamburger shop sold a combined total of 389 hamburgers and cheeseburgers on Thursday. There were 61 fever cheeseburgers

allsm [11]

Answer:

225

Step-by-step explanation:

Let h represent the number of hamburgers sold. Then h-61 is the number of cheeseburgers sold. The combined total is ...

h +(h -61) = 389

2h = 450 . . . . . . add 61

h = 225 . . . . . . . divide by 2

There were 225 hamburgers sold on Thursday.

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3 years ago

How do you compare two-way frequencies in a relative frequency table

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For example, here's how we would make column relative frequencies:
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3 0

3 years ago

What is 10 times as much as 1.0

sveta [45]

10 times 1.0 is 10 itself
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3 0

3 years ago

Read 2 more answers

Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?

vichka [17]

Answer:

The expression $-1+14i$ represents the number $2i^4-5i^3+3i^2+\sqrt{-81}$ rewritten in a+bi form.

Step-by-step explanation:

The value of $i$ is $i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4}$ in term of $i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}$

Substituting the value,

$i^{4}=\left(-1\right)\times \left(-1\right)$

Product of two negative numbers is always positive.

$\therefore i^{4}=1$

Now $i^{3}$ in term of $i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i$

Substituting the value,

$i^{3}=\left(-1\right)\times i$

Product of one negative and one positive numbers is always negative.

$\therefore i^{3}=-i$

Now $\sqrt{-81}$ can be written as follows,

$\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}$

Applying radical multiplication rule,

$\sqrt{ab}={\sqrt{a}}\sqrt{b}$

$\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}$

Now, $\sqrt{\left(81\right)=9$ and $\sqrt{-1}}=i$

$\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i$

Now substituting the above values in given expression,

$2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i$

Simplifying,

$2+5i-3+9i$

Collecting similar terms,

$2-3+5i+9i$

Combining similar terms,

$-1+14i$

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0

3 years ago

Are the expressions -0.5(3x + 5) and -1.5x + 2.5 equivalent? Explain why or why not.

Vikki [24]

No, they are not equivalent because if you distribute the -0.5 in the expression -0.5(3x+5) you will get -1.5x-2.5 which is not the same as -1.5+2.5

5 0

3 years ago