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Ratling [72]
3 years ago
15

H(x) = -x² + 3x + 10

Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0

Answer:

x = 5 or x = -2 or 3 - 2 x (derivative)

Step-by-step explanation:

Solve for x over the real numbers:

-x^2 + 3 x + 10 = 0

Multiply both sides by -1:

x^2 - 3 x - 10 = 0

x = (3 ± sqrt((-3)^2 - 4 (-10)))/2 = (3 ± sqrt(9 + 40))/2 = (3 ± sqrt(49))/2:

x = (3 + sqrt(49))/2 or x = (3 - sqrt(49))/2

sqrt(49) = sqrt(7^2) = 7:

x = (3 + 7)/2 or x = (3 - 7)/2

(3 + 7)/2 = 10/2 = 5:

x = 5 or x = (3 - 7)/2

(3 - 7)/2 = -4/2 = -2:

Answer: x = 5 or x = -2

____________________________________

Find the derivative of the following via implicit differentiation:

d/dx(H(x)) = d/dx(10 + 3 x - x^2)

Using the chain rule, d/dx(H(x)) = ( dH(u))/( du) ( du)/( dx), where u = x and d/( du)(H(u)) = H'(u):

(d/dx(x)) H'(x) = d/dx(10 + 3 x - x^2)

The derivative of x is 1:

1 H'(x) = d/dx(10 + 3 x - x^2)

Differentiate the sum term by term and factor out constants:

H'(x) = d/dx(10) + 3 (d/dx(x)) - d/dx(x^2)

The derivative of 10 is zero:

H'(x) = 3 (d/dx(x)) - d/dx(x^2) + 0

Simplify the expression:

H'(x) = 3 (d/dx(x)) - d/dx(x^2)

The derivative of x is 1:

H'(x) = -(d/dx(x^2)) + 1 3

Use the power rule, d/dx(x^n) = n x^(n - 1), where n = 2.

d/dx(x^2) = 2 x:

H'(x) = 3 - 2 x

Simplify the expression:

Answer:  = 3 - 2 x

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In the given graph point B is a relative maximum with the coordinates (0, 2).

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In the given graph, we need to find which point is a relative maximum.

<h3>What are relative maxima?</h3>

The function's graph makes it simple to spot relative maxima. It is the pivotal point in the function's graph. Relative maxima are locations where the function's graph shifts from increasing to decreasing. A point called Relative Maximum is higher than the points to its left and to its right.

In the graph, the maximum point is (0, 2).

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8 0
2 years ago
Sphere A and Sphere B , are similar. The volumes of A and B, are 17 and 136 cubic centimetres, respectively. The diameter of B ,
xxMikexx [17]

Answer:

3

Step-by-step explanation:

Given: Sphere A and Sphere B are similar.

The volumes of A and B are 17 cm^3and 136

The diameter of B is 6 cm.

To find: diameter of A

Solution:

Let R denotes radius of sphere A and r denotes radius of sphere B.

Radius of sphere A= R

Diameter of sphere B = 6 cm

So, radius of sphere B (r) = \frac{6}{2}=3\,\,cm

Volume of sphere is \frac{4}{3}\pi(radius)^3

Volume of sphere A = \frac{4}{3}\pi(R)^3

\frac{\frac{4}{3}\pi R^3}{\frac{4}{3}\pi r^3}=\frac{17}{136}=\frac{1}{8}\\\frac{R^3}{r^3}=\frac{1}{8}\\\frac{R}{r}=\frac{1}{2}\\r=2R

Put r = 3 cm

3=2R\\R=\frac{3}{2}=1.5\,\,cm

Diameter of sphere A = 2 × Diameter

= 2 × 1.5

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A gym charges 60$ per month and 50$ enrollment fee at the beginning of the membership write an equation in slope intercept form
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Answer:

y = 60x + 50

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Let y be the total price and x be the months passed,

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The table shows the relationship between a hedgehog's
Tpy6a [65]

The weight would the hedgehog lose during 115 day in hibernation is 3.45 ounces.

<h3>How much weight would the hedgehog lose during 115 day in hibernation?</h3>

Using proportions, it exits found that the hedgehog loses 3.45 ounces after 115 days of hibernation.

A proportional relationship exists modeled by: y = kx

In which k exists the constant of proportionality.

In this problem, the ratio between the weight loss after x days in hibernation is given by:

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Since this ratio exists constant, the relationship is proportional, modeled by:

y = 0.03 x

The weight lost after 115 days of hibernation is y(115), hence:

y = 0.03(115) = 3.45

The hedgehog loses 3.45 ounces after 115 days of hibernation.

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He used six elevenths more the first batch
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