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3241004551 [841]
2 years ago
14

Which of the following options best describes the function graphed below?

Mathematics
1 answer:
hodyreva [135]2 years ago
6 0
C.
The graph looks like it’s linear and is trending in an increasing way.
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Name the plane represented by the front of the box.
andre [41]

Answer:

FBC

Step-by-step explanation:

It's the only one at the front of the box

3 0
2 years ago
If Rihanna deposite 1500 rupees in the school fund at 9 p.C.P.A for 2 years, what is the total amount she will get?
S_A_V [24]

Answer: 1770 rupees

Step-by-step explanation:

To solve this, we first calculate the simple interest which will be:

= (P × R × T) / 100

= (1500 × 9% × 2) / 100

= (1500 × 0.09 × 2) / 100

= 270

The total amount tha she'll get will be:

= 1500 + 270

= 1770 rupees

3 0
2 years ago
-7x+5=-16 what is the answer
koban [17]

First move +5 to to the other side.

-7x=-16-5

-7x=-21

Then after this devide both sides by negative seven.

X=3

3 0
3 years ago
Read 2 more answers
I di not understand these any help greatly appreciated thank you
Rzqust [24]

Answer:

Step-by-step explanation:

First you need to convert it to a linear expression.

3x - y = 4

+3x        +3x

-1y = 3x + 4

---  ----- -----

-1     -1    -1

y = -3x -4

6x - 2y = 7

-6x         -6x

-2y = -6x + 7

----    -----   -----

-2       -2     -2

y = 3x - 3.5

-3x - 4 = 3x - 3.5

+3x         +3x

-4 = 6x - 3.5

+3.5       +3.5

-0.5 = 6x

-----   -----

6         6

-0.5

------ =  x

6

4 0
2 years ago
three distinct vertices of a cube are to be randomly chosen what is the probability that they will be the vertices of an equilat
jasenka [17]

The triangle formed by the vertices would be equilateral if the sides of the triangle coincide with the diagonals of the square face that defines the cube. See the attached sketch if that description is unclear.

Count the number of equilateral triangles that are possible. Such a triangle will always use up 3 vertices of the cube, and separate 1 vertex from the remaining 4. This means there are as many equilateral triangles as there are corners in the cube: 8.

Count the total number of triangles that can be made. From the 8 available vertices, we only need 3. If we fix 3 vertices, it doesn't matter in which order we connect them to make a triangle, so we count the number of combinations of 8 vertices taking 3 at a time, which is

\dbinom 83 = \dfrac{8!}{3!(8-3)!} = 56

Then the probability of forming an equilateral triangle is 8/56 = 1/7.

3 0
2 years ago
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