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3 years ago

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If x = 45, y = 63, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answ

er to the nearest hundredth. triangles ABC and ADC in which angle C is a right angle, point D is on segment BC between points B and C, the measure of angle ABD is x degrees, and the measure of angle ADC is y degrees 0.74 units 1.17 units 1.64 units 2.14 units

1 answer:

Alexandra [31]3 years ago

4 0

Answer:

1.17 units

Step-by-step explanation:

Given :

If x = 45, y = 63, and the measure of AC = 4 units, what is the difference in length between segments AB and AD?

x= 45° ; y = 63° AC = 4 units

From trigonometry,

Taking triangle ADC;

sinθ = opposite / Hypotenus

Sin63° = 4 / AD

AD = 4 / 0.891 = 4.489 units

From triangle ABC;

sin45° = 4 / AB

AB = 4 / 0.7071

AB = 5.656 units

Difference = (5.657 - 4.489) units

= 1.167 units

= 1.17 units (nearest hundredth)

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$\green{\large\underline{\sf{Solution-}}}$

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