(5g2+6g-10) -(6b2+2g+9)
1 answer:
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Solution:
We have: In the attached image, observe rectangle triangle ΔBAD
Use the Pythagorean Theorem:
BD = √(AB² + AD²)
BD = √(2² + 4²)
BD = √(4 + 16)
BD = √20
In the attached image, observe rectangle triangle ΔBDH
Use the Pythagorean Theorem:
BH = √(BD² + DH²)
BH = √(√20² + 5²)
BH = √(20 + 25)
BH = √45
BH = √(9 × 5)
BH = √9 × √ 5
BH = 3√5
BH = 3 × 2.24
BH = 6.72 cm
We have: In the attached image, observe rectangle triangle ΔBAD
Use the Pythagorean Theorem:
BD = √(AB² + AD²)
BD = √(2² + 4²)
BD = √(4 + 16)
BD = √20
In the attached image, observe rectangle triangle ΔBDH
Use the Pythagorean Theorem:
BH = √(BD² + DH²)
BH = √(√20² + 5²)
BH = √(20 + 25)
BH = √45
BH = √(9 × 5)
BH = √9 × √ 5
BH = 3√5
BH = 3 × 2.24
BH = 6.72 cm