All categories

3 years ago

Helppppppppppppppppppppppppp

Mathematics

2 answers:

Alchen [17]3 years ago

8 0

Answers:

6. 4x
7. 3y
8. y - 4.5
9. 3.5x + 2

Maslowich3 years ago

7 0

Answer:

I can't seem to solve these but hope this information helps :)

Step-by-step explanation:

Remove any grouping symbol such as brackets and parentheses by multiplying factors.

Use the exponent rule to remove grouping if the terms are containing exponents.

Combine the like terms by addition or subtraction.

Combine the constants.

You might be interested in

according to a recent survey, in 2000, 64% of households had one or more pets.Throughout the next decade, this decreased by appr

ehidna [41]

Answer:

Year 2034

Step-by-step explanation:

In 2000, 64% had one or more pets

Since decreasing at 1% per year, we can say:

In 2001, 63%

In 2002, 62%

In 2003, 61%

In 2004, 60%

And so on

To go to 30% from 60% in 2004, we would need to decrease 60 - 30 = 30%, and that will occur after 30 more years. So that would be the year

2004 + 30 = 2034

So, year 2034

3 0

3 years ago

Can someone answer these questions

Finger [1]

23. -7
24. greater. For example, when u subtract -5 from 10, the answer is 15, which is greater than 10
25. the pattern each term is subtracted 5 from it's previous term

4 0

3 years ago

What does -m+8=4m-7 equal

Olegator [25]

Answer:

Step-by-step explanation:

-m+8=4m-7

8=4m-(-m)-7

8=4m+m-7

8=5m-7

5m=8+7

5m=15

m=15/5

m=3

5 0

3 years ago

Read 2 more answers

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours of production time

user100 [1]

The question is incomplete, here is the complete question

Recall the production model from Section 1.3:

Max 10x

s.t. 5x ≤ 40

x ≥ 0

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours for each unit produced. Assume total production capacity remains 40 units. Use y as the number of units of product 2 produced. . Show the mathematical model when both products are considered simultaneously.

Answer:

Max Profit: 10x + 5y

5x + 2y ≤ 40

x ≥ 0, y ≥ 0

Explanation:

x= number of units of product 1 produced

y = number of units of product 2 produced

Since the first product, x, has a unit profit of $10 and Max1 is 10x

Second product, y, has a unit profit of $5, Max2 = 5y

The maximum profit when both products are considered simultaneously is 10x + 5y

Max Profit = 10x + 5y

Time required for each unit of x is 5hours

Therefore, time required for x units is 5x hours

Time required for each unit of y is 2hours

Therefore, time required for y units is 2y hours

Time required for the simultaneous production of both products is 5x + 2y

Since production capacity remains 40 units, 5x+2y ≤40

NB: The values of x and y cannot be negative

5 0

3 years ago

Someone help me with this

puteri [66]

Answer:

A) t = 1 second to reach the highest point

B) h = 96 feet

C) t = 3.449 seconds to hit the ground

Step-by-step explanation:

We notice that the equation that describes the position of the object in terms of the time, is a parabola (quadratic) with negative leading coefficient. therefore this is a parabola with arms pointing down, and with vertex at the top. It is at that top vertex that the maximum altitude of the object is reached.

We need therefore to find the position of the vertex (time "t" is the horizontal coordinate and height "h" is the vertical coordinate).

We know that the vertex (maximum of a parabola of this type - normally described by $y=ax^2+bx+c$ ) is given by $x_{vertex} = -\frac{b}{2*a}$ . Therefore in our case, understanding that time "t" is equivalent to the variable "x", and eight "h" is equivalent to the variable "y", that "-16" is $a$ , and "32" is $b$ , we have that the maximum occurs for:

$t_{max}=-\frac{32}{2*(-16)} = \frac{-32}{-32} = 1$

which means at one second from the launching.

We then can find the answer to part B by replacing t with "1" second in the formula for the height "h":

$h(1)=-16*(1)^2+32(1)+80=-16+32+80=96$

That is : a height of 96 feet.

To find the answer for part C: the time to hit the ground, we solve for the variable "t" in the given expression for the height, by setting the height to zero (object touching the ground) and using the quadratic formula:

$0=-16t^2+32t+80\\t=\frac{-32+/-\sqrt{32^2-4*(-16)*80} }{2*(-16)} \\ t=\frac{-32+/-\sqrt{6144} }{-32}$

which gives us two solutions: t = -1.449 seconds, and t = 3.449 seconds

Since the negative time does not have physical meaning in our case (time before the object was launched), we adopt the second answer: t = 3.449 seconds

5 0

3 years ago