The midpoint of a segment
A(-12;-3); B(3;-8)
X/2 +3y = 6 . . . . . . . . starting point
x/2 = 6 -3y . . . . . . . . subtract terms that don't have x
x = 2(6 -3y) . . . . . . . . multiply by the inverse of the x-coefficient
x = 12 -6y . . . . . . . . . expand if you like
3y = 6 -x/2 . . . . . . . . subtract terms that don't have y
y = (6 -x/2)/3 . . . . . . . multiply by the inverse of the y-coefficient
y = 2 -x/6 . . . . . . . . . expand if you like
Answer:
2/3 or 0.67
Step-by-step explanation:
Slope = y2 - y1 /x2 - x1
Given
x1 = 1
y1 = 8
x2 = 9
y2 = 12
Slope = 12 - 8 /9 - 1
= 4/6
Reduce is by 2
2/3
Or
0.67
Answer: IT EQUALS 2
Step-by-step explanation:
The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
