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Leokris [45]
2 years ago
9

Give the domain, range, intercepts, asymptotes, intervals of increasing and decreasing, intervals of positive and negative, symm

etry and extrema (if any) for the graph of this equation.
3/x^2-4 + 1
Mathematics
1 answer:
klemol [59]2 years ago
3 0
y = \frac{3}{x^{2} - 4} + 1

Domain: x² - 4 ≠ 0
                 + 4 + 4
                    x² ≠ 4
                 √x² ≠ √4
                    x ≠ ±2
           x ≠ -2 and x ≠ 2
     (-∞, -2) ∨ (-2, 2) ∨ (2, ∞)

Range: y ≠ 1
    (-∞, 1) ∨ (1, ∞)

Intervals: Increasing: (0.25 , ∞)
              Decreasing: (-∞, 0.25)

Symmetry: X-axis: Not Symmetric
                  Y-axis: Not Symmetric
                  Origin: Not Symmteric

Extrema: Maximum Relative: x = 0
                Minimum Relative: Nothing
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CaHeK987 [17]
The expression to find the number of notebooks James bought would be written as:

Number of notebooks = total spent / cost per item

Number of notebooks = (2y^2 + 6) / <span>(y^2 − 1)

</span><span>If y = 3, then the number of notebooks bought would be:

</span>Number of notebooks = (2y^2 + 6) / (y^2 − 1)
Number of notebooks = (2(3)^2 + 6) / (3^2 − 1)
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The jazz band has 13 members. To raise money for a tour, each member sold r raffle tickets. Write an expression that shows the n
Hunter-Best [27]

Answer:

13 * r

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5 0
3 years ago
Consider the line y = 2x–4.
choli [55]

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--------------------------

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8 0
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Vika [28.1K]

Answer:

[D] -552.5 feet

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[RevyBreeze]

5 0
2 years ago
Please can some explain how to identify angles that on the same segment? ​
sp2606 [1]

Step-by-step explanation:

Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.

Picture 1  a° = a°  they are the same

Picture 2  p= 52°  q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.

Picture 3 + 4  Let the obtuse angle MOQ = 2x.  

Using the circle theorem, the angle at the centre is twice   the angle at the circumference.

Therefore picture 4 tells us and proves;

Angle MNQ = x and angle MPQ = x.

Picture 5

A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.

The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.

Picture 6

The opposite angles in a cyclic quadrilateral add up to 180°.

a + c = 180°

b + d = 180°

Picture 7

Example

Calculate the angles a and b.

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This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °

So hopefully this will help you remember the format here for quadrilateral shapes within a circle.

b = 180 - 140 = 40°

a = 180 - 60 = 120°

8 0
3 years ago
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