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saw5 [17]
3 years ago
10

HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?

Mathematics
2 answers:
tangare [24]3 years ago
8 0

Answer:

y=-(x-7)(x+3)

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

y=-(x+3)(x-7) but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is y=a(x-h)^2+k.

This is called vertex form because it gives you the vertex is (h,k).

We are given that (h,k)=(2,25) which makes our equation:

y=a(x-2)^2+25.

We can find the value of a by plugging in the x-intercept (7,0) for (x,y) into:

y=a(x-2)^2+25

0=a(7-2)^2+25

0=a(5)^2+25

Subtract 25 on both sides:

-25=a(5)^2

-25=a(25)

Divide both sides by 25:

\frac{-25}{25}=a

-1=a.

So the equation for the quadratic is:

y=-1(x-2)^2+25

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

y=-1(x-2)(x-2)+25

y=-1(x^2-2x-2x+4)+25

y=-1(x^2-4x+4)+25

y=-x^2+4x-4+25

y=-x^2+4x+21

Factor out -1:

y=-(x^2-4x-21)

WE need to find two numbers that multiply to be -21 and add to be -4:

y=-(x-7)(x+3)

vladimir2022 [97]3 years ago
8 0

Answer:

On edu answer is D. f(x)=(x+3)(x-7)

Step-by-step explanation:

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