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Digiron [165]
3 years ago
14

Solve each equation for 0 degrees < x < 360 degrees.

Mathematics
2 answers:
grigory [225]3 years ago
4 0

Answer:

120 degrees and 330 degrees

Step-by-step explanation:

Solve each equation for 0 degrees < x < 360 degrees.

Sqrt 2 cos x + 1 = 0

A.45,315

B.115,245

C.135,225

D.46, 314

Please Help ASAP!

Given the expression √(2cosx+1) = 0

Square both sides of the equation;

√(2cosx+1) = 0

2cosx + 1 = 0

2cosx = -1

cos x = -1/2

x = cos^-1(-1/2)

x = -60 degrees

Since cos is negative in the 2nd and 3rd quadrant then;

x = 180-60 = 120 degrees (2nd quadrant)

x = 270+60 = 330 degrees (3rd quadrant)

UNO [17]3 years ago
4 0

Answer:It C

Step-by-step explanation:

3pi/4 = 135 , 5pi/4 += 225

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