Answer:
3
Step-by-step explanation:
Period of a function is the period after which the function attains the same value
in the graph attached with this problem we can see that
f(0)=1
the value of x for which function f(x) attains the value 1 again is at
x=3
f(3)=1
similarly , we see
f(6)=1 , f(9)=1
Hence we see that after every increased value of x by 3 units , we attain the same value of function . hence the period of the function is 3
Answer:
6. x = 28 degrees
7. z = 1.6 cm
Step-by-step explanation:
6.
Notice that you can use the property that tells us that the addition of all internal angles of a triangle must give 180 degrees, then you write the following equation:
50 + 69 + (2 x +5) = 180
combine like terms:
119 + 2 x + 5 = 180
124 + 2 x = 180
subtract 124 from both sides:
2 x = 56
divide by 2 both sides:
x = 56 / 2
x = 28 degrees
Problem 7.
If the two triangles are congruent, then the side MN must equal side RS.
Since MN measure 1,8 cm, then RS must also measure 1.8 cm
and we can write the equation:
1.8 = 3 z - 3
adding 3 to both sides:
1.8 + 3 = 3 z
4.8 = 3 z
dividing both sides by 3:
z = 4.8 / 3
z = 1.6 cm
For example, for LCM (12,30) we find:
Using the set of prime numbers from each set with the highest exponent value we take 22 * 31 * 51 = 60. Therefore LCM (12,30) = 60.
Answer:
19°
Step-by-step explanation:
I have attached an image showing this elevation.
From the image, let's first find the angle A by using cosine rule.
Thus;
8.1² = 5.5² + 13.1² - 2(5.5 × 13.1)cos A
65.61 = 30.25 + 171.61 - 144.1cos A
144.1cos A = 171.61 + 30.25 - 65.61
144.1cosA = 136.25
cosA = 136.25/144.1
cosA = 0.9455
A = cos^(-1) 0.9455
A = 19°
The standard form of a hyperbola is <span><span><span>x2/</span><span>a2 </span></span>− y<span><span>2/ </span><span>b2 = 1
the tangent line is the first derivative of the function</span></span></span><span>y′ = <span>b^2x/ a^2 y
hence the slope is </span></span><span>m = <span>b^2 x0 / <span>a^2 <span>x1
</span></span></span></span>Therefore the equation of the tangent line isy−x1 = b^2 x0 / a^2 x1* (x−x0)
