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Alexeev081 [22]
3 years ago
10

WILL GIVE YOU BRAINLIEST

Mathematics
2 answers:
Phoenix [80]3 years ago
8 0
It should have only one
VladimirAG [237]3 years ago
5 0

Answer:

only 1

Step-by-step explanation: I just did the test and i got an A+!!

You are so very welcome!!

Come to my help anytime!!

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What is the value of f(x) = 36x when x =1/2
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The value of f(x) is 18 because when there is 1/2, think about half (i think like that). so what is the half of 36? 18.
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PLEASE ANSWER OMG PLEASE An expression is shown below:
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14ck *2 + 10ck *2 - 16ck - 40k
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Which of the following points are more than 5 vertical units away from the point (0,-2) ? Choose all that
Igoryamba
The 1st question it’s (0,4) and (0,-8). The second is a quadrilateral
3 0
3 years ago
You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then
gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is  d\theta_1  =(14.36p)^o

Step-by-step explanation:

From the question we are told that

    The angle of elevation  is  \theta_1  =  15 ^o =  \frac{\pi}{12}

     The height of the tree is  h

      The distance from the base is  D

h is mathematically represented as

            h  = D tan \theta       Note : this evaluated using SOHCAHTOA i,e

                                               tan\theta  =  \frac{h}{D}

Generally for small angles the series approximation of  tan \theta \  is

          tan \theta  =  \theta  + \frac{\theta ^3 }{3}

So given that \theta =  15 \ which \ is \ small

       h = D (\theta + \frac{\theta^3}{3} )

       dh = D (1 + \theta^2) d\theta

=>        \frac{dh}{h} =  \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta

Now from the question the relative error of height should be at  most

        \pm  p%

=>    \frac{dh}{h} =   \pm p

=>    \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta  = \pm p

=>      d\theta  =  \pm  \frac{\theta +  \frac{\theta^3}{3} }{1+ \theta ^2} *    \ p

 So  for   \theta_1

            d\theta_1  =  \pm  \frac{\theta_1 +  \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} *    \ p

substituting values  

          d [\frac{\pi}{12} ]  =  \pm  \frac{[\frac{\pi}{12} ] +  \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} *    \ p

 =>       d\theta_1  = 0.25 p

Converting to degree

           d\theta_1  = (0.25* 57.29) p

            d\theta_1  =(14.36p)^o

4 0
3 years ago
What happens to the value of the expression 3e3e3, e as eee increases?<br> Choose 1 answer:
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