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damaskus [11]
3 years ago
12

How many solutions does this equation have?

Mathematics
2 answers:
vodka [1.7K]3 years ago
7 0
Infinite solutions

4x-5=x-5+3x
combine like terms
4x - x -3x= 5-5
0=0
Igoryamba3 years ago
3 0
Once you simplify with the combination of like terms and “bringing the baby to the mom” (moving x), you’ll figure out that all real numbers are solutions. Hope this helps!!
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1.) Natalie is a lab technician and earns $10.65 per hour. What are her wages for 40 Hours?
Contact [7]

Answer:

Add

Step-by-step explanation:

10.65*40=426

426+50=476

5 0
3 years ago
How many 0.4 L glasses can be filled from<br> a 4.75 L jug of juice?
nata0808 [166]

Answer:

11

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A furniture store owner buys a sofa for $400 and marks it up %90 to sell it. During the stores anniversary sale she sells the so
lord [1]

Answer:

Anniversary sale price= $570

Step-by-step explanation:

Giving the following information:

Purchase cost= $400

Mar-up percentage= 90%

<u>First, we need to calculate the "normal" selling price:</u>

Selling price= 400*1.9= $760

<u>Now, we can determine the anniversary sale price:</u>

Anniversary sale price= 760 - (760*0.25)= $570

3 0
2 years ago
Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda
pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

Step-by-step explanation:

Given equation is

x^2y'' - 9xy+24y=0

This Euler Cauchy type differential equation.

So, we can let

y=x^m

Differentiate with respect to x

y'= mx^{m-1}

Again differentiate with respect to x

y''= m(m-1)x^{m-2}

Putting the value of y, y' and y'' in the differential equation

x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0

\Rightarrow m(m-1)x^m-9mx^m+24x^m=0

\Rightarrow m^2-m-9m+24=0

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

y_1(x)=x^4

and

y_2(x)=x^6

First we compute the Wronskian

W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|

         = \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|

         =x⁴×6x⁵- x⁶×4x³    

        =6x⁹-4x⁹

        =2x⁹

       ≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

5 0
3 years ago
99 POINTS!!! JUST ANSWER THIS QUESTION, PLEASE!!!
-Dominant- [34]

Hi!

I would approach this question by first looking at where the parallelogram is located, by graphing the image. I did so and drew a rough image on Paint (See attached image)

To get the part where the diagonals intersect, I would find the midpoint of the line between points (1, 3) and (5,-9) (or the other pair). The reason is a parallelogram's diagonals always bisect each other, meaning the point they intersect is always the middle of the two diagonals.

Therefore, you can find the midpoint of a diagonal, between (1, 3) and (5, -9). The midpoint theorem is (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}.

Take the points (1, 3) and (5, -9), and fill them in.

(\frac{1 + 5}{2} , \frac{3 - 9}{2})

Then solve.

(\frac{6}{2}, \frac{-6}{2})

(3, -3)

If you'd like to check the other midpoint:

Take the points, (8, 3) and (-2, -9)

(\frac{8 - 2}{2}, \frac{3 - 9}{2})

Then solve.

(\frac{6}{2} , \frac{-6}{2})

(3, -3)

They're the same, so that answer is correct.

Hope this helps!

8 0
3 years ago
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