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2 years ago

How many solutions does this equation have?

Mathematics

2 answers:

vodka [1.7K]2 years ago

7 0

Infinite solutions

4x-5=x-5+3x
combine like terms
4x - x -3x= 5-5
0=0

Igoryamba2 years ago

3 0

Once you simplify with the combination of like terms and “bringing the baby to the mom” (moving x), you’ll figure out that all real numbers are solutions. Hope this helps!!

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Write an equation of the line that passes through the given points.<br><br> (0,−3),(3,3)

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I find it easiest to use slope-intercept form, or y=mx+b, to do this.

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3 years ago

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2 years ago

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

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$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

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$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$

Neither solution makes any denominator be zero, so both are good solutions.

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Dovator [93]

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2 years ago

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guapka [62]

Answer:

Step-by-step explanation:

there are two ways to answer : since angle 1 and the 125 degree angle are a linear pair, you can do 180-125 = 55, or, since the three angles in the triangle always add up to 180, you can do 180-37-88 = 55.

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2 years ago

Read 2 more answers