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nasty-shy [4]
3 years ago
10

8(-a+4)=-6a-8+8a Can y’all help me

Mathematics
1 answer:
NeTakaya3 years ago
3 0

Answer:

a = 14.4

Step-by-step explanation:

8a/8 = a       8(-a+4)/8=-a+4      equation is now    -a+4=-6a-8

-6a/-6 = a      -a/-6=1/6a    equation is now   1/6a + 4 = a-8

a-8 + 8 = a      1/6a + 4 + 8 = 1/6a + 12     equation is now     a = 1/6a+12

5/6 are left of the variable  12/5=2.4    12 + 2.4 = 14.4

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ICE Princess25 [194]

Answer:

  • 4x² - 13x + 8 = 0
  • 4x² - 11x + 5 = 0
  • 16x² - 41x + 1 = 0
  • x² + 5x + 4 = 0
  • x² - 66x + 64 = 0

Step-by-step explanation:

<u>Given</u>

  • α and β are roots of 4x²-5x-1=0

<u>Then the sum and product of the roots are:</u>

  • α+b = -(-5)/4 = 5/4
  • αβ = -1/4

(i) <u>Roots are α + 1 and β + 1, then we have:</u>

  • (x - (α + 1))(x - (β + 1)) = 0
  • (x - α - 1)(x - β - 1) = 0
  • x² - (α+β+2)x + α+β+ αβ + 1 = 0
  • x² - (5/4+2)x +5/4 - 1/4 + 1 = 0
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  • 4x² - 13x + 8 = 0

(ii) <u>Roots are 2 - α and 2 - β, then we have:</u>

  • (x + α - 2)(x + β - 2) = 0
  • x² + (a + β - 4)x - 2(α + β) + αβ + 4 = 0
  • x² + (5/4 - 4)x - 2(5/4) - 1/4 + 4 = 0
  • x² - 11/4x - 10/4 - 1/4 + 16/4 = 0
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  • 4x² - 11x + 5 = 0

(iii) <u>Roots are α² and β², then:</u>

  • (x - α²)(x-β²) = 0
  • x² -(α²+β²)x + (αβ)² = 0
  • x² - ((α+β)² - 2αβ)x + (-1/4)² = 0
  • x² - ((5/4)² -2(-1/4))x + 1/16 = 0
  • x² - ( 25/16 + 1/2)x + 1/16 = 0
  • x² - 33/16x + 1/16 = 0
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(iv) <u>Roots are 1/α and 1/β, then:</u>

  • (x - 1/α)(x - 1/β) = 0
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(v) <u>Roots are 2/α² and 2/β², then:</u>

  • (x - 2/α²)(x - 2/β²) = 0
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Answer:

The system of equations is

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see the attached figure

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Answer:

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