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3 years ago

Questio

Mathematics

1 answer:

horsena [70]3 years ago

4 0

Шаг за шагом вперёд и только потом я поняла это только начало анализа

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1, Formalize the following arguments and verify whether they are valid:

kobusy [5.1K]

Answer:

They cannot be attempted from user mode.

Explanation:

We cannot attempt privileged instruction from user mode, only we can attempt from kernel mode because these instructions are exclusive for this mode.

3 0

3 years ago

HELP ASAP PLZ

WARRIOR [948]

You can use the formula to solve for the y-values in the table. Insert the x-value into the equation: y = 2x - 2

(ex. y = 2(1)-2)

So..

x | y

0 | -2

1 | 0

3 | 4

5 | 8

8 | 14

10 | 18

[First time answering on Brainly so I accidentally commented the answer instead. Don’t know how to delete the comment but anyways, I hope my response helped you!]

4 0

3 years ago

What are the rise and run of the line whose equation is y=15x?

Blababa [14]

Answer:

Rise = 15.

Run = 1.

Step-by-step explanation:

Hope this helps!

5 0

3 years ago

Help! (tell me if you can’t see it)

Anna35 [415]

Answer:

B. y=7x+3

Step-by-step explanation:

You find the changes of y over the changes of x. y sub 2 - y sub 1 divided by x sub 2 over x sub 1. So, 17 - 10 over 2 - 1 = 7. 3 is the y-intercept. y=7x+3

4 0

3 years ago

A personnel director in a particular state claims that the mean annual income is the same in one of the state's counties (Coun

Shalnov [3]

Answer:

a) The hypothesis that the mean annual income is the same could not be rejected. There is no enough evidence to claim they are different.

b) The critical values for this two-sided test are t=±1.711.

Step-by-step explanation:

The question is incomplete:

(a) Identify the claim and state H0 and Ha.

Which is the correct claim below?

(b) Find the critical value(s) and identify the rejection region(s).

Enter the critical value(s) below.

We have an hypothesis test on the difference of two means.

The null and alternative hypothesis are:

$H_0: \mu_a-\mu_b=0\\\\H_a: \mu_a-\mu_b\neq 0$

The claim of the alternative hypothesis is that the mean annual income is different in County A and County B.

The null hypothesis is that the mean annual income is equal in both counties.

The significance level is α=0.10.

The sample from County A has a mean of S40,400, a s.d. of $8,700 and a sample size of 18 residents.

The sample from County B has a mean of S39,200, a s.d. of $6,000 and a sample size of 8 residents.

The standard error of the difference of means is:

$\sigma_d=\sqrt{\frac{\sigma_a^2}{n_a}+\frac{\sigma_b^2}{n_b}}=\sqrt{\frac{8700^2}{18}+\frac{6000^2}{8}}=\sqrt{8705000}=2950$

The degrees of freedom are:

$df=n_a+n_b-2=18+8-2=24$

Then, the test statistic is:

$t=\frac{\Delta M-\Delta \mu}{\sigma_d} =\frac{(40,400-39,200)-0}{2950} =\frac{1200}{2950}=0.407$

For a statistic t=0.407, and df=24, the P-value is P=0.69. As the P-value is bigger than the significance level, the null hypothesis failed to be rejected.

If we would use the critial value approach, we would have to calculate the critical values for t, for df=24, two sided test and α=0.10.

The critical values, looking in a table, are t=1.711.

5 0

3 years ago