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Marina86 [1]
3 years ago
7

PLEASE HELP!

Mathematics
1 answer:
Rama09 [41]3 years ago
5 0
If you Multiply 42.00 and 0.30 because 30 percent as a decimal is 0.30 once your done you should get 12.6 then you subtract 12.6 from 42.00 you get 29.40 once you're done with that you multiply that product from 25% or 0.25 and you would get $7.35.
meaning that you're answer would be $7.35 please make brainliest 
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A circle has a radius of \sqrt{13}√ ​13 ​ ​​ square root of, 13, end square root units and is centered at (-9.3,4.1)(−9.3,4.1)le
timofeeve [1]

Answer:  The equation of the circle is

x^2+y^2+18.6x-8.2y+90.3=0.

Step-by-step explanation:  We are given to write the equation of the circle with radius √13 units and center at the point (-9.3, 4.1).

We know that

the standard equation of a circle with radius r units and center at the point (h, k) is given by

(x-h)^2+(y-k)^2=r^2.

In the given circle,

radius, r = √13 units  and  center, (h, k) = (-9.3, 4.1).

Therefore, the equation of the circle will be

(x-(-9.3))^2+(y-4.1)^2=(\sqrt{13})^2\\\\\Rightarrow (x+9.3)^2+(y-4.1)^2=13\\\\\Rightarrow x^2+18.6y+86.49+y^2-8.2y+16.81=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+103.3=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+90.3=0.

Thus, the equation of the circle is

x^2+y^2+18.6x-8.2y+90.3=0.

7 0
3 years ago
What number is 80% of 66
Anni [7]
52.8 is the answer.


Hope this helps!
4 0
4 years ago
$119 croquet set 50% discount
natta225 [31]
119 times .5 equals $59.5

$119-$59.5=$59.5
6 0
3 years ago
Read 2 more answers
Please help, find what X is. 42 - X = 29
Bumek [7]

Answer:

X = 13

Step-by-step explanation:

42 - X = 29

Subtract 42 from each side

42-42 - X = 29-42

-X = -13

Multiply each side by -1

X = 13

3 0
3 years ago
Read 2 more answers
Find two numbers x and y with a sum of 2 and a difference of 12
Law Incorporation [45]

Answer:

x = 7

y = -5

Step-by-step explanation:

x + y = 2

x - y = 12

( x + y ) + ( x - y ) = 2 + 12

2x = 14

x = 7

7 + y = 2

y = -5

Check:

7 + -5 = 2

7 - (-5) = 12

Correct

-Chetan K

4 0
2 years ago
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