Answer:
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 9 - 1 = 8
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.8595
The margin of error is:
M = T*s = 1.8595*2.7 = 5
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 25.3 - 5 = 20.3 milligrams
The upper end of the interval is the sample mean added to M. So it is 25.3 + 5 = 30.3 milligrams.
The 90% confidence interval for the mean nicotine content of this brand of cigarette is between 20.3 milligrams and 30.3 milligrams.
Answer:
Felix has 250 dollars
No change
Lucas has 5 dollars
Step-by-step explanation:
Answer:
3960 Degrees
Step-by-step explanation:
There is a formula for this!
In this n=24 since there are 24 sides.
The formula is 180(n-2).
Hope this helped and please mark me as Brainliest if possible.
Answer:
The probability is 0.173
Step-by-step explanation:
The probability is of winning is 0.75 = 75/100 = 3/4
This means that the probability of losing is 0.25 = 25/100 = 1/4
So if they are two win 4 games, they will lose three
We can get this probability using the Bernoulli approximation of the binomial theorem
So here, we have
P(X = 4) = 7 C 4 * 0.75^4 * 0.25^3
= 0.173034667969
which is approximately 0.1730