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Vera_Pavlovna [14]
3 years ago
8

Herky found that 8 out of every 100 beans in his garden were nibbled by rabbits. how many beans can he expect to be damaged if t

here are 450 beans in his garden?
Mathematics
2 answers:
galben [10]3 years ago
6 0
First, find the unit rate, which is, out of how many beans will 1 be nibbled by a rabbit. We can do this by dividing the amount of beans by the amount that had been nibbled:

\sf 100\div 8=12.5

So one out of every 12.5 beans are nibbled on. There are 450 beans in his garden, we can divide our unit rate by this to find out how many he can expect to be damaged:

\sf 450\div 12.5=36

So he can expect 36 beans in his garden to be damaged.
Igoryamba3 years ago
5 0

Answer:

36

Step-by-step explanation:

I know my stuffs

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Could -2 be used to rewrite 32
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Answer:Look at this list of whole number powers of -2:

(-2)0 = 1

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Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

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