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erma4kov [3.2K]
3 years ago
15

15.4 = -2.1 + a 0.2help pleasee​

Mathematics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

a = 3.5

Step-by-step explanation:

15.4=-2.1+\frac{a}{0.2} \\\\\frac{a}{0.2} =15.4+2.1\\\\\frac{a}{0.2} =17.5\\\\a=3.5

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The following data represent the weights in pounds of a sample of 25 police officers:
DochEvi [55]

Given:

The data values are:

164, 148, 137, 157, 173, 156, 177, 172, 169, 165, 145, 168, 163, 162, 174, 152, 156, 168, 154, 151, 174, 146, 134, 140, and 171.

To find;

a. Lower quartile.

b. Upper quartile.

c. Interquartile range.

Solution:

We have,

164, 148, 137, 157, 173, 156, 177, 172, 169, 165, 145, 168, 163, 162, 174, 152, 156, 168, 154, 151, 174, 146, 134, 140, 171.

Arrange the data values in ascending order.

134, 137, 140, 145, 146, 148, 151, 152, 154, 156, 156, 157, 162, 163, 164, 165, 168, 168, 169, 171, 172, 173, 174, 174, 177.

Divide the data values in two equal parts.

(134, 137, 140, 145, 146, 148, 151, 152, 154, 156, 156, 157), 162, (163, 164, 165, 168, 168, 169, 171, 172, 173, 174, 174, 177)

Divide each parentheses in two equal parts.

(134, 137, 140, 145, 146, 148), (151, 152, 154, 156, 156, 157), 162, (163, 164, 165, 168, 168, 169), (171, 172, 173, 174, 174, 177)

a. Location of lower quartile is:

Q_1=\dfrac{1}{4}(n+1)\text{th term}

Q_1=\dfrac{1}{4}(25+1)\text{th term}

Q_1=\dfrac{26}{4}\text{th term}

Q_1=6.5\text{th term}

The lower quartile of the weights is:

Q_1=\dfrac{148+151}{2}

Q_1=\dfrac{299}{2}

Q_1=149.5

Therefore, the location of the lower quartile of the weights is between 6th term and the 7th term. The value of the lower quartile is 149.5.

b. Location of upper quartile is:

Q_3=\dfrac{3}{4}(n+1)\text{th term}

Q_3=\dfrac{3}{4}(25+1)\text{th term}

Q_3=\dfrac{3\cdot 26}{4}\text{th term}

Q_3=19.5\text{th term}

The upper quartile of the weights is:

Q_3=\dfrac{169+171}{2}

Q_3=\dfrac{340}{2}

Q_3=170

Therefore, the location of the upper quartile of the weights is between 19th term and the 20th term. The value of the upper quartile is 170.

c. The interquartile range of the given data set is:

IQR=Q_3-Q_1

IQR=170-149.5

IQR=20.5

Therefore, the interquartile range of the weights is 20.5.

7 0
3 years ago
I WILL GIVE BRAINLIEST PLZ ANSWER DUE IN A FEW MINUTES<br><br><br> What is every factor of 116
Maslowich

Answer:

1,2,4,29,58,116

Step-by-step explanation:

Prime factorization 116=2x2x29

8 0
3 years ago
Read 2 more answers
Help with the second question. I'm stuck.
IRISSAK [1]
(1/12) / 10 = 1/x.....1/12 distance to 10 min = whole distance(12/12) or 1 to x min
cross multiply
(1/12)(x) = (10)(1)
1/12x = 10
x = 10 / (1/12)
x = 10 * 12
x = 120 minutes or 2 hrs 

I am not sure if u do it this way...but this will get u the answer
4 0
4 years ago
The number has 9 digits. the digit in the tenths place is the digit used to represent a half dozen. the digit in the tens place
laiz [17]
48,.842,610.6 is the number I would say. Sorry if I'm wrong.
8 0
4 years ago
PLS DO BOTH PROBELMS
bezimeni [28]

<em>1.) </em><em>510 miles</em>

<em>Take the values you have been given which is 153 miles and 3 gallons of gas </em>

<em>Now divide 153 by 3 to find put the Miles per gallon (MPG)</em>

<em>153/3=51</em>

<em>now take 51 and multiply it by 10</em>

<em>51x10=</em><em>510</em>

<em>2.) </em><em>$16 per yard of plywood</em>

<em>Let's take the values we have been given </em>

<em>3/4 of a yard of plywood and $12 for it</em>

<em>Now let's divide it </em>

12/ 3/4=$16

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3 years ago
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