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cluponka [151]
2 years ago
5

Animals were trapped in a city and later released into the wild. A random sample of the data is provided in the table below.

Mathematics
1 answer:
Fynjy0 [20]2 years ago
6 0

Answer:

c

1,400

Step-by-step explanation:

We take the sample proportion of skunks and estimate for the entire population.

Sample:

140 skunks out of 230 + 140 + 120 = 490 animals.

140/490 = 0.28571428571

If a random sample of 5,000 animals are trapped in the city, how many skunks would be estimated to be included?

0.28571428571 out of 5000. So

0.28571428571*5000 = 1429

Close to 1400, which means that the answer is given by option C.

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2 years ago
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Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

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2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

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3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

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