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xxTIMURxx [149]
3 years ago
11

Mike has a stack of 10 cars number 1 to 10. If he randomly chooses to cards without replacing the first car drawn, what is the p

robability that Mike would pick two cars are less than five?
Mathematics
1 answer:
olasank [31]3 years ago
5 0
Im sorry i dont really know
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(3m±4/5n)2<br>solve this question<br>​
sukhopar [10]

Answer:

(3m-4/5)2  

Final result :

 (15m - 4)2

 ——————————

     52    

Step by step solution :

Step  1  :

           4

Simplify   —

           5

Equation at the end of step  1  :

        4

 (3m -  —)2

        5

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  5  as the denominator :

          3m     3m • 5

    3m =  ——  =  ——————

          1        5    

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

3m • 5 - (4)     15m - 4

————————————  =  ———————

     5              5    

Equation at the end of step  2  :

 (15m - 4)

(—————————)2

     5    

Step  3  :

Final result :

 (15m - 4)2

 ———

     52    

Step-by-step explanation:

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Answer:

($2.19,$2.39)

Step-by-step explanation:

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Is this in the right order?
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Answer:

yes it is in the right order

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15 3/14+ 24 1/14+ 12 2/7+ 12 2/7+ 10 1/7 +10 1/7+ 35 3/7=​
lesantik [10]

Answer:

it is :119.5714

Step-by-step explanation:

15 3/14+24 1/14+12 2/7+12 2/7+10 1/7+10 1/7+35 3/7=

step by step now:

15 3/14+24 1/14+12 4/14+12 4/14+10 2/14+10 2/14+35 6/14=118 22/14=118+1.5714=119.5714

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3 years ago
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